保存一对一的关系。两个表中的外键

save one to one relationship. foreign keys in both tables

我有如下两个表:

CREATE TABLE pets(
      id int NOT NULL AUTO_INCREMENT,
          user_id int,
          any_data varchar(255),
      foreign key (user_id) references users(id),
      primary key(`id`)
);

CREATE TABLE users(
      id int NOT NULL AUTO_INCREMENT,
          pet_id int,
          any_data varchar(255),
      foreign key (pet_id) references pets(id),
      primary key(`id`)
);

我的模型有下一个:

用户:

public function relatedPet() {
    return $this->hasOne("Pet", "pet_id");
}

宠物:

public function relatedUser() {
    return $this->belongsTo("User", "user_id ");
}

我想保存一个用户并关联一个现有的宠物,但我不知道该怎么做:

$user= new User(array("any_data"=>"Hi, this is a test"));
$pet = Pet::find(1);

如何创建两个对象之间的关系?

首先您的用户 table 不需要 pet_id。算了吧。那么

Users 型号

public function pet()
{
    return $this->hasOne('App\Pet'); // Changed form hasMany to hasOne
}

Pet 型号

public function user()
{
    return $this->belongsTo('App\User');
}

现在创建一个新的User

$user = \App\User::create($data); // You need to set $fillable property
$pet = \App\Pet::findOrfail($id)
$pet->user()->associate($user);
$pet->save();

示例:

$user = \App\User::findOrFail($id);
$pet = $user->pet

// Inserting a new user and a pet
$anotherUser = \App\User::create($data);
$anotherPet = new \App\Pet($data);
$anotherUser->pet()->save($anotherPet);

$pet = \App\Pet::findOrFail($id);
$user = $pet->user

// Inserting a new pet, a user and then associating them
$anotherPet = \App\Pet::create($data);
$anotherUser = \App\User::create($data);
$anotherPet->user()->associate($anotherUser);
$anotherPet->save()