在一行中显示两个不同的 JSON 结果

Question

我是 JSON、Google Maps APIs DistanceMatrix 和 Places
的新手我正在尝试显示来自两个不同 JSON 结果

的结果

基本上都是两个不同的"lists"

编辑
对于 object_json 我从我的坐标中获取所有附近的地方，然后我将获取每个结果的 places_id 并使用它来查询距离矩阵 api 并获取每个距离 object_json2

代码

    #name and types from Places API
    lines = (f"{s['name']}: {', '.join(r.replace('_', ' ') for r in s['types'])} -" for s in object_json['results'][0:5])
    #distance from DistanceMatrix API
    lines2 = (f"{t['distance']['text']}" for t in item['elements'] for item in object_json2['rows'])

样本JSON object_json：获取名称、类型和places_id

   "results" : [
      {
         "name" : "Joe’s Thai Kitchen",
         "place_id" : "ChIJIadbw8sb2jER3i-OvZSCBGk",
         "types" : [ "restaurant", "food", "point_of_interest", "establishment" ],
      },

object_json2 根据附近的搜索结果，得到places_id，得到每个元素distance的距离矩阵结果

"rows" : [
      {
         "elements" : [
            {
               "distance" : {
                  "text" : "0.3 km",
                  "value" : 303
               },
               "duration" : {
                  "text" : "2 mins",
                  "value" : 123
               },
               "status" : "OK"
            },
            {
               "distance" : {
                  "text" : "90 m",
                  "value" : 90
               },
               "duration" : {
                  "text" : "1 min",
                  "value" : 36
               },
               "status" : "OK"
            }
         ]
      }
   ],

前两个结果

Joe’s Thai Kitchen: restaurant, food, point of interest, establishment - ['0.4 km', '77 m', '0.3 km', '0.8 km', '0.3 km']

Hong Kong Street Chun Kee: restaurant, food, point of interest, establishment - ['0.4 km', '77 m', '0.3 km', '0.8 km', '0.3 km']

想要的前两个结果

Joe’s Thai Kitchen: restaurant, food, point of interest, establishment - 0.4 km
Hong Kong Street Chun Kee: restaurant, food, point of interest, establishment - 77 m

希望有人能帮忙谢谢。

Answer 1

首先，我认为您没有正确解释 Distance Maxtrix API 的结果。这也导致 the XY Problem.

但无论如何，您实际要做的是加入 object1 和 object2 中两个列表的结果。您可以使用 zip() 执行此操作。 zip() 接受给定的每个可迭代对象和 returns 每个列表的第 n^th 元素的元组。并停在最短的一个：

>>> list(zip('ABCD', 'xyz'))
[('A', 'x'), ('B', 'y'), ('C', 'z')]

假设 object_json 看起来像这样：

object_json = {
    "results" : [
        {
            "name" : "Joe’s Thai Kitchen",
            "place_id" : "ChIJIadbw8sb2jER3i-OvZSCBGk",
            "types" : [ "restaurant", "food", "point_of_interest", "establishment" ],
        },
        {
            "name" : "Hong Kong Street Chun Kee",
            "place_id" : "KgbcszVo-I3reJ2BS8WBDAijiHc",
            "types" : [ "restaurant", "food", "point_of_interest", "establishment" ],
        }
    ]
}

根据您的示例使用 object_json2：

>>> lines = (f"{s['name']}: {', '.join(r.replace('_', ' ') for r in s['types'])} -" for s in object_json['results'][0:5])
>>> lines2 = (f"{t['distance']['text']}" for item in object_json2['rows'] for t in item['elements'])
>>>
>>> [' '.join((x, y)) for x, y in zip(lines, lines2)]
['Joe’s Thai Kitchen: restaurant, food, point of interest, establishment - 0.3 km',
 'Hong Kong Street Chun Kee: restaurant, food, point of interest, establishment - 90m'
]

（顺便说一句，在您的代码中，这一行是语法错误：lines2 = (f"{t['distance']['text']}" for t in item['elements'] for item in object_json2['rows'])。第二个 for 循环应该先出现。）

在一行中显示两个不同的 JSON 结果

Display two different JSON results in one line

python

json

google-places-api

google-distancematrix-api