Laravel 7 Symfony 5 更新后出现电子邮件异常

Laravel 7 email exceptions broke after Symfony 5 update

我已经升级到 Laravel 7.1,现在使用 Symfony 5 这些 类 不再存在:

use Symfony\Component\Debug\Exception\FlattenException;
use Symfony\Component\Debug\ExceptionHandler as SymfonyExceptionHandler;

我在我的 app\Exceptions\Handler.php 文件中使用它们在异常重新抛出时发送电子邮件通知并且它们在 Laravel 6 中运行良好,但是当我从 [=35] 升级时出现故障=] 到 7.1.2 也升级到 Symfony 5.

我用这些替换了前面提到的 类:

use Symfony\Component\ErrorHandler\ErrorRenderer\HtmlErrorRenderer;
use Symfony\Component\ErrorHandler\Exception\FlattenException;

然后替换为:

$e = FlattenException::create($exception);
$handler = new SymfonyExceptionHandler();
$html = $handler->getHtml($e);

有了这个:

$e = FlattenException::create($exception);
$handler = new HtmlErrorRenderer();
$content = $handler->getBody($e);

有效,但现在我不再像以前那样在电子邮件中获取调试内容,而是收到一条更基本的错误消息,因为它是针对 public.

您可以在此处查看不同格式的示例: https://symfony.com/doc/current/controller/error_pages.html

我确定我遗漏了一些简单的东西,但我还没有想出如何让它向我发送详细的异常数据,就像我在升级之前获得的那样。

有什么建议吗?

要获得 html 的完整响应,只需使用:

$html = ExceptionHandler::convertExceptionToResponse($e);

这是完整的Handler.php代码

<?php

namespace App\Exceptions;

use Log;
use Mail;
use Exception;
use Throwable;
use App\Mail\ErrorNotification;
use Illuminate\Database\Eloquent\ModelNotFoundException;
use Symfony\Component\HttpKernel\Exception\HttpException;
use Illuminate\Foundation\Exceptions\Handler as ExceptionHandler;
use Symfony\Component\HttpKernel\Exception\NotFoundHttpException;


class Handler extends ExceptionHandler
{

    /**
     * A list of the exception types that should not be reported.
     *
     * @var array
     */
    protected $dontReport = [
        HttpException::class,
        ModelNotFoundException::class,
    ];

    /**
     * Report or log an exception.
     *
     * This is a great spot to send exceptions to Sentry, Bugsnag, etc.
     *
     * @param  \Exception  $e
     * @return void
     */
    public function report(Throwable $e)
    {
        if ($this->shouldReport($e)) {
            $this->sendEmail($e);
        }

        return parent::report($e);
    }

    /**
     * Render an exception into an HTTP response.
     *
     * @param  \Illuminate\Http\Request  $request
     * @param  \Exception  $e
     * @return \Illuminate\Http\Response
     */
    public function render($request, Throwable $e)
    {
        if ($e instanceof ModelNotFoundException) {
            $e = new NotFoundHttpException($e->getMessage(), $e);
        }

        return parent::render($request, $e);
    }


    public function sendEmail(Throwable $e)
    {
        try {

            $html = ExceptionHandler::convertExceptionToResponse($e);

            Mail::to('youremailhere@gmail.com')->send(new ErrorNotification($html));

        } catch (Exception $ex) {
            Log::error($ex);
        }
    }

}

下面是我最终用来在异常通知电子邮件中获取我想要的结果的代码。我之前遗漏的主要部分是我没有将真实值传递到 HtmlErrorRender class 以引发调试标志。此处显示更正后的行:

new HtmlErrorRenderer(true);

这是我现在为 app/Exceptions/Handler.php 文件

使用的完整代码
<?php

namespace App\Exceptions;

use Illuminate\Foundation\Exceptions\Handler as ExceptionHandler;
use Log;
use Throwable;
use Symfony\Component\ErrorHandler\ErrorRenderer\HtmlErrorRenderer;
use Symfony\Component\ErrorHandler\Exception\FlattenException;

class Handler extends ExceptionHandler
{
    /**
     * A list of the exception types that are not reported.
     *
     * @var array
     */
    protected $dontReport = [
    ];

    /**
     * A list of the inputs that are never flashed for validation exceptions.
     *
     * @var array
     */
    protected $dontFlash = [
        'password',
        'password_confirmation',
    ];

    /**
     * Report or log an exception.
     *
     * @param  \Throwable  $exception
     * @return void
     *
     * @throws \Exception
     */
    public function report(Throwable $exception)
    {
        if ($this->shouldReport($exception)) {
            $this->sendEmail($exception); // sends an email
        }
        parent::report($exception);
    }

    /**
     * Render an exception into an HTTP response.
     *
     * @param  \Illuminate\Http\Request  $request
     * @param  \Throwable  $exception
     * @return \Symfony\Component\HttpFoundation\Response
     *
     * @throws \Throwable
     */
    public function render($request, Throwable $exception)
    {
        if ($exception instanceof \Illuminate\Session\TokenMismatchException) {  //https://gist.github.com/jrmadsen67/bd0f9ad0ef1ed6bb594e
            return redirect()
                ->back()
                ->withInput($request->except('password'))
                ->with('errorMessage', 'This form has expired due to inactivity. Please try again.');
        }

        return parent::render($request, $exception);
    }

    /**
     * Sends an email to the developer about the exception.
     *
     * @return void
     */
    public function sendEmail(Throwable $exception)
    {
        try {
            $e = FlattenException::create($exception);
            $handler = new HtmlErrorRenderer(true); // boolean, true raises debug flag...
            $css = $handler->getStylesheet();
            $content = $handler->getBody($e);

            \Mail::send('emails.exception', compact('css','content'), function ($message) {
                $message
                    ->to('youremailhere@gmail.com')
                    ->subject('Exception: ' . \Request::fullUrl())
                ;
            });
        } catch (Throwable $ex) {
            Log::error($ex);
        }
    }
}

$css 和 $content 被传递到位于 resources/views/emails/exception.blade.php 的视图中。我在该文件中的代码如下:

<!DOCTYPE html>
<html>
    <head>
        <meta charset="UTF-8" />
        <style>{!! $css ?? '' !!}</style>
    </head>
    <body>
        {!! $content ?? '' !!}
    </body>
</html>

测试答案后,我得到一些错误 "Parssing to Exception class",所以如果您使用 Laravel 7,您需要使用 "createFromThrowable" 代替 "create" 以获得兼容使用 Throwable 对象。