Faker 得到 streetAddress 抛出 ErrorException

Question

我正在构建一个 laravel 应用程序，我已经创建了一个 FakerServiceProvider 来填充用于测试和本地开发的工厂。

<?php

namespace App\Providers;

use Faker\Factory;
use Faker\Generator;
use Faker\Provider\en_GB\Address;
use Faker\Provider\en_GB\Person;
use Faker\Provider\en_GB\PhoneNumber;
use Illuminate\Contracts\Support\DeferrableProvider;
use Illuminate\Support\ServiceProvider;

/**
 * Class FakerServiceProvider
 * @package App\Providers
 */
class FakerServiceProvider extends ServiceProvider implements DeferrableProvider
{
    /**
     *
     */
    public function register()
    {
        $this->app->singleton(Generator::class, function ($app) {
            $factory = Factory::create('en_GB');
            $factory->addProvider(Person::class);
            $factory->addProvider(Address::class);
            $factory->addProvider(PhoneNumber::class);

            return $factory;
        });
    }

    /**
     * @return array
     */
    public function provides()
    {
        return [Generator::class];
    }
}

我创建了一个地址工厂：

<?php

use App\Address;
use App\Country;

$factory->define(Address::class, function (Faker\Generator $faker) {
    return [
        'line_1' => $faker->secondaryAddress,
        'line_2' => $faker->streetAddress,
        'town' => $faker->city,
        'county' => $faker->county,
        'country_id' => factory(Country::class)->make()->id,
        'postcode' => $faker->postcode,
        'phone' => $faker->phoneNumber,
    ];
});

当我尝试使用该工厂时出现以下错误： ErrorException: call_user_func_array() expects parameter 1 to be a valid callback, non-static method Faker\Provider\Address::streetAddress() should not be called statically

我检查了 Faker 库的源代码，有一个 streetAddress 方法 here

我试过同时调用 $faker->streetAddress 和 $faker->streetAddress()with no luck. I would expect$faker->streetAddressto produce something like ` 或类似的东西。

谁能帮我解释一下这个问题

Answer 1

删除 Faker Service Provider 中添加的提供程序修复了问题

Faker 得到 streetAddress 抛出 ErrorException

Faker get streetAddress throwing ErrorException

laravel

factory

faker