使用 etree 解析 xml 时无法 return 子值

Unable to return child values when parsing xml using etree

我有一个 xml 文件看起来像

<?xml version="1.0" encoding="UTF-8" ?>
<FullReport
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
    <firm>1426</firm>
    <reportDate>07FEB2020_18:00:00.000000</reportDate>
    <rooms>
        <room>
            <roomID>PCHAT-0x0000000000000637</roomID>
            <roomTitle>FX - WBB - CTON</roomTitle>
            <description>global chat</description>
            <creationDate></creationDate>
            <removalDate></removalDate>
            <lastActivityDate>02/07/2020 12:26:24</lastActivityDate>
            <status>Active</status>
            <membership>Bilateral</membership>
            <isAnonymous>false</isAnonymous>
            <hasActiveAdmins>true</hasActiveAdmins>
            <activeUserCount>17</activeUserCount>
            <distinctFirmsInRoom>2</distinctFirmsInRoom>
            <isInternalOnly>false</isInternalOnly>
            <isIncognitoForum>false</isIncognitoForum>
        </room>
        <users>
            <uuid>6820</uuid>
            <bbgEmail>SJONES@Bloomberg.net</bbgEmail>
            <fullName>SEAN JONES</fullName>
            <firmName>BANK OF TEST</firmName>
            <firmNumber>1400</firmNumber>
            <accountNumber>51067</accountNumber>
            <accountName>BANK OF TEST</accountName>
            <inviteDate>01/07/2013 22:00:39</inviteDate>
            <isDeleted>false</isDeleted>
            <isAdmin>false</isAdmin>
            <isCreator>false</isCreator>
            <roomAlias>CTON</roomAlias>
            <corpEmail>sean.jones@botest.com</corpEmail>
            <city>LONDON</city>
        </users>
        <users>
            <uuid>6820</uuid>
            <bbgEmail>SSMITH@Bloomberg.net</bbgEmail>
            <fullName>SEAN SMITH</fullName>
            <firmName>BANK OF TEST</firmName>
            <firmNumber>1400</firmNumber>
            <accountNumber>51067</accountNumber>
            <accountName>BANK OF TEST</accountName>
            <inviteDate>01/07/2013 22:00:39</inviteDate>
            <isDeleted>false</isDeleted>
            <isAdmin>false</isAdmin>
            <isCreator>false</isCreator>
            <roomAlias>CTON</roomAlias>
            <corpEmail>sean.smith@botest.com</corpEmail>
            <city>LONDON</city>
        </users>
</FullReport>
</FullReport>

我正在使用以下代码解析数据:

import xml.etree.cElementTree as et

tree = et.parse('test.xml')
print (tree.getroot())
root = tree.getroot()
print ("tag=%s, attrib=%s" % (root.tag, root.attrib))

for child in root:
        print (child.tag, child.attrib)
        if child.tag == "room":
            for step_child in child:
                print (step_child.tag)

# get the information via the children!
print ("-" * 40)
print ("Iterating using a getchildren()")
print ("-" * 40)
rooms = root.getchildren()
for room in rooms:
    room_children = room.getchildren()
    for room_child in room_children:
        print ("%s=%s" % (room_child.tag, room_child.text))

当我打印 room_child.tag 和 room_child.text 时,我没有看到这些值?对此很陌生,所以我不确定我错过了什么?

返回的结果是:

我的最终目标是遍历每个值并转换为 CSV,但我无法访问这些值并且不确定为什么没有数据返回。我希望最终的 csv 看起来类似于 csv

中每个用户的一行

当你 运行 for child in root: 时,这个循环只迭代 FullReport 的直接后代,在你的例子中:firmreportDaterooms,所以它没有机会到达room,这是 位于低一级。

从你的代码(第一个循环)我看出你真的很感兴趣 在 FullReport/rooms/room.

的直系后代中

要打印他们的标签名称和文本内容,您可以运行例如:

for child in root.iter('room'):
    for step_child in child:
        print(f'{step_child.tag:20} {step_child.text}')

对于您的样本输入,结果是:

roomID               PCHAT-0x0000000000000637
roomTitle            FX - WBB - CTON
description          global chat
creationDate         None
removalDate          None
lastActivityDate     02/07/2020 12:26:24
status               Active
membership           Bilateral
isAnonymous          false
hasActiveAdmins      true
activeUserCount      17
distinctFirmsInRoom  2
isInternalOnly       false
isIncognitoForum     false

就你的最终任务而言,你可以运行:

rows = []
for child in root.iter('rooms'):
    roomId, roomTitle = 'id', 'ttl'
    for it in child:
        if it.tag == 'room':
            roomId = it.findtext('roomID')
            roomTitle = it.findtext('roomTitle')
        elif it.tag == 'users':
            rows.append([roomId, roomTitle, it.findtext('uuid'), it.findtext('bbgEmail'),
                it.findtext('fullName'), it.findtext('firmName')])
df = pd.DataFrame(rows, columns=['roomId', 'roomTitle', 'uuid', 'bbgEmail',
    'fullName', 'firmName'])

上面的代码是基于 room 元素先出现的假设 在它们之后是 users 个元素。

并添加有关 post 中未显示的任何其他列的代码。