Python Shutil 移动失败：找不到文件

Question

我在下面的代码中收到一个错误，上面写着 FileNotFoundError: [WinError 2] The system cannot find the file specified: 'Harry White.txt' -> 'C:\Users\johna\Desktop\z_testingmove\Harry White\Harry White.txt'

谁能帮帮我？

import shutil
import os, sys

source = 'C:\Users\johna\Desktop\z_testingmove'
dest1 = 'C:\Users\johna\Desktop\z_testingmove\Harry White'
dest2 = 'C:\Users\johna\Desktop\z_testingmove\John Smith'
dest3 = 'C:\Users\johna\Desktop\z_testingmove\Judy Jones'

files = os.listdir(source)

for f in files:
    if f == "Harry White.txt":
        shutil.move(f, dest1)
    elif f == "John Smith.txt":
        shutil.move(f, dest2)
    elif f == "Judy Jones.txt":
        shutil.move(f, dest3)

Answer 1

您对 shutil.move 函数的理解有误。

shutil.move(src, dst)

Recursively move a file or directory (src) to another location (dst) and return the destination.

src和dst必须是文件或目录的full path。

您必须更改代码，试试这个：

import shutil
import os, sys

source = 'C:\Users\johna\Desktop\z_testingmove'
dest1 = 'C:\Users\johna\Desktop\z_testingmove\Harry White'
dest2 = 'C:\Users\johna\Desktop\z_testingmove\John Smith'
dest3 = 'C:\Users\johna\Desktop\z_testingmove\Judy Jones'

files = os.listdir(source)
for filename in files:
    sourcepath = os.path.join(source, filename)
    if filename == "Harry White.txt":
        destpath = os.path.join(dest1, filename)
        shutil.move(sourcepath, destpath)
    elif filename == "John Smith.txt":
        destpath = os.path.join(dest2, filename)
        shutil.move(sourcepath, destpath)
    elif filename == "Judy Jones.txt":
        destpath = os.path.join(dest3, filename)
        shutil.move(sourcepath, destpath)

Python Shutil 移动失败：找不到文件

Python Shutil move failing: File Not Found

python

shutil