HTML/JS Canvas 甜甜圈图 如何创建重叠的圆形笔画?
HTML/JS Canvas Donut Chart How to create round strokes with overlap?
我的圆环图无法正常工作,这是我的问题。我想创建一个这样的圆环图:
但是我的甜甜圈图现在是这样的:
如您所见,笔划在正确的方向上没有重叠。我想这可能是因为我开始从右到左画笔画。相反,它应该从左到右绘制它们,所以左边的“圆角端”是可见的,而不是右边的圆角端。
这是我目前尝试过的方法:
//function to draw the donut chart, ctx = context, cx - cy = position, radius and arcwith
dmbChart(ctx, cx, cy, radius, arcwidth) {
var tot = 0;
var accum = 0;
var PI = Math.PI;
var PI2 = PI * 2;
var offset = -PI/2;
for(var i = 0; i < this.canvasValues.length; i++) {
tot += this.canvasValues[i];
}
//Donut Sectors Color: Draw each stroke based on the value (canvasValues) and Color (canvasColors)
for(var i = 0; i < this.canvasValues.length; i++) {
ctx.lineWidth = arcwidth;
ctx.beginPath();
ctx.lineCap = "round";
ctx.arc(cx, cy, radius, offset + PI2 * (accum/tot), offset + PI2 * ((accum + this.canvasValues[i]) / tot));
ctx.strokeStyle = this.canvasColors[i];
ctx.stroke();
accum += this.canvasValues[i];
}
}
如你所见,我得到的值是每个笔画应该有多长的百分比和颜色。从顶部开始,我从顶部 -> 右侧 -> 底部 -> 左侧绘制每一个,这就是结果。但是我怎样才能修改它以获得最上面的结果?
编辑:
在@Helder Sepulveda 的帮助下,我现在这样创建了它。我更改了很多计算,修复了更改带来的一些错误。现在唯一的问题是它没有在顶部开始绘制。如您所见,绿色笔划应该从顶部开始:
function dmbChart(ctx, cx, cy, radius, arcwidth) {
var canvasValues = [30, 5, 15, 10, 10, 10, 10, 10];
var canvasColors = ["#10dc60", "#DDDDDD", "#0cd1e8", "#ffce00", "#7044ff", "#f04141", "#ffea00", "#ee82ee"];
ctx.lineWidth = arcwidth;
ctx.lineCap = "round";
var accum = canvasValues.reduce((a,b) => a + b, 0);
for (var i = canvasValues.length-1; i >= 0; i--) {
var radians = canvasValues[i] / 100 * 360 * Math.PI / 180
ctx.beginPath();
ctx.arc(cx, cy, radius, accum, accum - radians, true);
ctx.strokeStyle = canvasColors[i];
ctx.stroke();
accum -= radians;
}
ctx.beginPath();
ctx.arc(cx, cy, radius, accum, accum - (0.1 / 100 * 360 * Math.PI / 180), true);
ctx.strokeStyle = canvasColors[canvasColors.length - 1];
ctx.stroke();
}
const canvas = document.getElementById("c");
canvas.width = canvas.height = 140;
const ctx = canvas.getContext("2d");
dmbChart(ctx, 70, 70, 50, 30)
<canvas id="c"></canvas>
我正在对 canvasValues
和 canvasColors
做一些假设来证明一些有用的东西:
function dmbChart(ctx, cx, cy, radius, arcwidth) {
var accum = 0;
var PI = Math.PI;
var PI2 = PI * 2;
var offset = -PI / 2;
var canvasValues = [10, 10, 10]
var canvasColors = ["red", "green", "blue"]
var tot = canvasValues.reduce((a, b) => a + b, 0)
ctx.lineWidth = arcwidth;
ctx.lineCap = "round";
for (var i = 0; i < canvasValues.length; i++) {
ctx.beginPath();
ctx.arc(cx, cy, radius, offset + PI2 * (accum / tot), offset + PI2 * ((accum + canvasValues[i]) / tot));
ctx.strokeStyle = canvasColors[i];
ctx.stroke();
accum += canvasValues[i];
}
ctx.beginPath();
ctx.arc(cx, cy, radius, offset, offset);
ctx.strokeStyle = canvasColors[0];
ctx.stroke();
}
const canvas = document.getElementById("c");
canvas.width = canvas.height = 140;
const ctx = canvas.getContext("2d");
dmbChart(ctx, 70, 70, 50, 30)
<canvas id="c"></canvas>
想法是在循环结束时用第一个值(和颜色)绘制最后一个 "short" 弧线
我还移出了循环中的几行:
ctx.lineWidth = arcwidth;
ctx.lineCap = "round";
可以在循环之前设置一次
这就是我们在评论中所说的反转方向
function dmbChart(ctx, cx, cy, radius, arcwidth) {
var PI = Math.PI;
var PI2 = PI * 2;
var offset = -PI / 2;
var canvasValues = [10, 10, 10]
var canvasColors = ["red", "green", "blue"]
var tot = canvasValues.reduce((a,b) => a + b, 0)
var accum = tot;
ctx.lineWidth = arcwidth;
ctx.lineCap = "round";
for (var i = canvasValues.length-1; i >= 0; i--) {
ctx.beginPath();
ctx.arc(cx, cy, radius, offset + PI2 * (accum / tot), offset + PI2 * ((accum + canvasValues[i]) / tot));
ctx.strokeStyle = canvasColors[i];
ctx.stroke();
accum -= canvasValues[i];
}
ctx.beginPath();
p = offset + PI2 * ((tot + canvasValues[canvasValues.length-1]) / tot)
ctx.arc(cx, cy, radius, p, p);
ctx.strokeStyle = canvasColors[canvasColors.length-1];
ctx.stroke();
}
const canvas = document.getElementById("c");
canvas.width = canvas.height = 140;
const ctx = canvas.getContext("2d");
dmbChart(ctx, 70, 70, 50, 30)
<canvas id="c"></canvas>
我的圆环图无法正常工作,这是我的问题。我想创建一个这样的圆环图:
但是我的甜甜圈图现在是这样的:
如您所见,笔划在正确的方向上没有重叠。我想这可能是因为我开始从右到左画笔画。相反,它应该从左到右绘制它们,所以左边的“圆角端”是可见的,而不是右边的圆角端。
这是我目前尝试过的方法:
//function to draw the donut chart, ctx = context, cx - cy = position, radius and arcwith
dmbChart(ctx, cx, cy, radius, arcwidth) {
var tot = 0;
var accum = 0;
var PI = Math.PI;
var PI2 = PI * 2;
var offset = -PI/2;
for(var i = 0; i < this.canvasValues.length; i++) {
tot += this.canvasValues[i];
}
//Donut Sectors Color: Draw each stroke based on the value (canvasValues) and Color (canvasColors)
for(var i = 0; i < this.canvasValues.length; i++) {
ctx.lineWidth = arcwidth;
ctx.beginPath();
ctx.lineCap = "round";
ctx.arc(cx, cy, radius, offset + PI2 * (accum/tot), offset + PI2 * ((accum + this.canvasValues[i]) / tot));
ctx.strokeStyle = this.canvasColors[i];
ctx.stroke();
accum += this.canvasValues[i];
}
}
如你所见,我得到的值是每个笔画应该有多长的百分比和颜色。从顶部开始,我从顶部 -> 右侧 -> 底部 -> 左侧绘制每一个,这就是结果。但是我怎样才能修改它以获得最上面的结果?
编辑: 在@Helder Sepulveda 的帮助下,我现在这样创建了它。我更改了很多计算,修复了更改带来的一些错误。现在唯一的问题是它没有在顶部开始绘制。如您所见,绿色笔划应该从顶部开始:
function dmbChart(ctx, cx, cy, radius, arcwidth) {
var canvasValues = [30, 5, 15, 10, 10, 10, 10, 10];
var canvasColors = ["#10dc60", "#DDDDDD", "#0cd1e8", "#ffce00", "#7044ff", "#f04141", "#ffea00", "#ee82ee"];
ctx.lineWidth = arcwidth;
ctx.lineCap = "round";
var accum = canvasValues.reduce((a,b) => a + b, 0);
for (var i = canvasValues.length-1; i >= 0; i--) {
var radians = canvasValues[i] / 100 * 360 * Math.PI / 180
ctx.beginPath();
ctx.arc(cx, cy, radius, accum, accum - radians, true);
ctx.strokeStyle = canvasColors[i];
ctx.stroke();
accum -= radians;
}
ctx.beginPath();
ctx.arc(cx, cy, radius, accum, accum - (0.1 / 100 * 360 * Math.PI / 180), true);
ctx.strokeStyle = canvasColors[canvasColors.length - 1];
ctx.stroke();
}
const canvas = document.getElementById("c");
canvas.width = canvas.height = 140;
const ctx = canvas.getContext("2d");
dmbChart(ctx, 70, 70, 50, 30)
<canvas id="c"></canvas>
我正在对 canvasValues
和 canvasColors
做一些假设来证明一些有用的东西:
function dmbChart(ctx, cx, cy, radius, arcwidth) {
var accum = 0;
var PI = Math.PI;
var PI2 = PI * 2;
var offset = -PI / 2;
var canvasValues = [10, 10, 10]
var canvasColors = ["red", "green", "blue"]
var tot = canvasValues.reduce((a, b) => a + b, 0)
ctx.lineWidth = arcwidth;
ctx.lineCap = "round";
for (var i = 0; i < canvasValues.length; i++) {
ctx.beginPath();
ctx.arc(cx, cy, radius, offset + PI2 * (accum / tot), offset + PI2 * ((accum + canvasValues[i]) / tot));
ctx.strokeStyle = canvasColors[i];
ctx.stroke();
accum += canvasValues[i];
}
ctx.beginPath();
ctx.arc(cx, cy, radius, offset, offset);
ctx.strokeStyle = canvasColors[0];
ctx.stroke();
}
const canvas = document.getElementById("c");
canvas.width = canvas.height = 140;
const ctx = canvas.getContext("2d");
dmbChart(ctx, 70, 70, 50, 30)
<canvas id="c"></canvas>
想法是在循环结束时用第一个值(和颜色)绘制最后一个 "short" 弧线
我还移出了循环中的几行:
ctx.lineWidth = arcwidth;
ctx.lineCap = "round";
可以在循环之前设置一次
这就是我们在评论中所说的反转方向
function dmbChart(ctx, cx, cy, radius, arcwidth) {
var PI = Math.PI;
var PI2 = PI * 2;
var offset = -PI / 2;
var canvasValues = [10, 10, 10]
var canvasColors = ["red", "green", "blue"]
var tot = canvasValues.reduce((a,b) => a + b, 0)
var accum = tot;
ctx.lineWidth = arcwidth;
ctx.lineCap = "round";
for (var i = canvasValues.length-1; i >= 0; i--) {
ctx.beginPath();
ctx.arc(cx, cy, radius, offset + PI2 * (accum / tot), offset + PI2 * ((accum + canvasValues[i]) / tot));
ctx.strokeStyle = canvasColors[i];
ctx.stroke();
accum -= canvasValues[i];
}
ctx.beginPath();
p = offset + PI2 * ((tot + canvasValues[canvasValues.length-1]) / tot)
ctx.arc(cx, cy, radius, p, p);
ctx.strokeStyle = canvasColors[canvasColors.length-1];
ctx.stroke();
}
const canvas = document.getElementById("c");
canvas.width = canvas.height = 140;
const ctx = canvas.getContext("2d");
dmbChart(ctx, 70, 70, 50, 30)
<canvas id="c"></canvas>