获取服务类型

Question

将 Client 实例作为 client 我可以执行 print client 并获取 Client 对象的字符串表示形式，即：

Suds ( https://fedorahosted.org/suds/ )  version: 0.4 GA  build: R699-20100913

Service ( RoutingService ) tns="http://tempuri.org/"
   Prefixes (11)
      ns0 = "http://schemas.datacontract.org/2004/07/Microsoft.Dynamics.AX.Framework.Services"
      ns1 = "http://schemas.microsoft.com/2003/10/Serialization/"
      ns2 = "http://schemas.microsoft.com/2003/10/Serialization/Arrays"
      ns3 = "http://schemas.microsoft.com/dynamics/2006/02/documents/EntityKey"
      ns4 = "http://schemas.microsoft.com/dynamics/2006/02/documents/EntityKeyList"
      ns5 = "http://schemas.microsoft.com/dynamics/2006/02/documents/QueryCriteria"
      ns6 = "http://schemas.microsoft.com/dynamics/2008/01/documents/Fault"
      ns7 = "http://schemas.microsoft.com/dynamics/2008/01/documents/LTExchCurrency"
      ns8 = "http://schemas.microsoft.com/dynamics/2008/01/sharedtypes"
      ns9 = "http://schemas.microsoft.com/dynamics/2010/01/datacontracts"
      ns10 = "http://tempuri.org"
   Ports (2):
      (serviceEndpoint)
         Methods (0):
         Types (2949):
            ns6:AifFault
            ns6:ArrayOfFaultMessage
            ns6:ArrayOfFaultMessageList
            ns0:ArrayOfInfologMessage
...

我想知道如何在不手动重新解析此字符串的情况下在 Python 对象中获取类型命名空间？

例如 ns6 代表 AifFault 类型。

Answer 1

怎么样：

print client.wsdl.tns

获取服务类型

Get service types

python

wsdl

suds