如何在 Webflux 中将 GroupBy 结果列表制作成新地图
How to make GroupBy result list to new Map in Webflux
如何在Webflux中将GroupBy结果列表制作成新的Map
这是我的输入列表和预期结果。那我应该怎么做才能得到结果呢
// expect
{
"timestamp": "2019-06-13T00:00:00.000",
"result": {
"first": 1,
"second": 2,
"third": 3
}
}
// input list
[
{
"timestamp": "2019-06-13T00:00:00.000",
"first": 1
},
{
"timestamp": "2019-06-13T00:00:00.000",
"second": 2
},
{
"timestamp": "2019-06-13T00:00:00.000",
"third": 3
}
]
val Flux.fromIterable(list)
.groupBy{it.timestamp}
.concatMap { groupItem ->
// here!! I want to make `group by result list to new Map``
Result(timestamp = groupItem.key()!!, Item(first = ?, second = ?, third =?))
}
我想通了。
Flux.merge(first, second, thrid)
.groupBy { it.timestamp }
.concatMap {
it.map { item ->
val container = mutableMapOf<String, Any>()
if (item is firstEntity) {
container["first"] = item.result.count
container["timestamp"] = it.key()!!
}
if (item is secondEntity) container["second"] = item.result.count
if (item is thridEntity) container["thrid"] = item.result.count
container
}.reduce { acc, current ->
acc.putAll(current)
acc
}
}
.map {
val first = (it["first"] ?: 0) as Int
val second = (it["second"] ?: 0) as Int
val thrid = (it["thrid"] ?: 0) as Int
val timestamp = (it["timestamp"] ?: "") as String
// somthing!!
}
如何在Webflux中将GroupBy结果列表制作成新的Map
这是我的输入列表和预期结果。那我应该怎么做才能得到结果呢
// expect
{
"timestamp": "2019-06-13T00:00:00.000",
"result": {
"first": 1,
"second": 2,
"third": 3
}
}
// input list
[
{
"timestamp": "2019-06-13T00:00:00.000",
"first": 1
},
{
"timestamp": "2019-06-13T00:00:00.000",
"second": 2
},
{
"timestamp": "2019-06-13T00:00:00.000",
"third": 3
}
]
val Flux.fromIterable(list)
.groupBy{it.timestamp}
.concatMap { groupItem ->
// here!! I want to make `group by result list to new Map``
Result(timestamp = groupItem.key()!!, Item(first = ?, second = ?, third =?))
}
我想通了。
Flux.merge(first, second, thrid)
.groupBy { it.timestamp }
.concatMap {
it.map { item ->
val container = mutableMapOf<String, Any>()
if (item is firstEntity) {
container["first"] = item.result.count
container["timestamp"] = it.key()!!
}
if (item is secondEntity) container["second"] = item.result.count
if (item is thridEntity) container["thrid"] = item.result.count
container
}.reduce { acc, current ->
acc.putAll(current)
acc
}
}
.map {
val first = (it["first"] ?: 0) as Int
val second = (it["second"] ?: 0) as Int
val thrid = (it["thrid"] ?: 0) as Int
val timestamp = (it["timestamp"] ?: "") as String
// somthing!!
}