在 R 中查找所有数字并将其转换为相应的名称

Question

我有一个单列数据框，其中每一行都是一条语句。这些语句主要是字母字符，但也有一些数字字符。我试图找到所有数字字符并将它们替换为相应的字母字符。

基本上，我想从这里开始

 "I looked at the watermelons around 12 today"
 "There is a dog on the bench"
 "the year is 2017"
 "I am not hungry"
 "He turned 1 today"

进入（或类似的东西）

 "I looked at the watermelons around twelve today"
 "There is a dog on the bench"
 "the year is two thousand seventeen"
 "I am not hungry"
 "He turned one today"

有我熟悉的将数字转换为单词的函数，例如 xfun 包中的 numbers_to_words 函数，但我不知道如何系统地为整个数据框执行此操作。

Answer 1

实际上我不知道一个简单的函数或类似的东西，但我有一个可能有点糟糕的解决方案给你：

library(xfun)
a <- "I looked at the watermelons around 12 today"        
y <- numeric(nchar(a))        
for(i in 1:nchar(a))        
{        
  y[i]<-as.numeric(substr(a,i,i))        
}        
x <- n2w(as.numeric(paste(na.omit(y), collapse="")))        
z <- which(y != "NA")        
paste(c(substr(a, 1, z[1]-1), x, substr(a, z[length(z)] + 1, nchar(a))), collapse = "")

目前只对一个数字有效

Answer 2

这是 stringr 和 english 包的一种方法。

library(stringr)
library(english)
data<-  c("I looked at the watermelons around 12 today", "There is a dog on the bench", "the year is 2017", "I am not hungry", "He turned 1 today")
Replacement <-  lapply(str_extract_all(data,"[0-9]+"),function(x){
                   as.character(as.english(as.numeric(x)))})

sapply(seq_along(data),
       function(i){
         ifelse(grepl('[0-9]+',data[i]),
                str_replace_all(data[i],"[0-9]+",Replacement[[i]]),
                data[i])})
[1] "I looked at the watermelons around twelve today" "There is a dog on the bench"                    
[3] "the year is two thousand seventeen"              "I am not hungry"                                
[5] "He turned one today"

在 R 中查找所有数字并将其转换为相应的名称

Finding and converting all numbers into their corresponding names in R

string

int

r

alphanumeric