Spring 文档 - 打开 API 3 - 如何将默认值设置为 body?

Spring docs - Open API 3 - How to set default values to body?

我正在使用 Spring 引导 + Spring 数据 Mongo + Spring REST + Spring HATEOAS实施 REST 端点。

因为我们要传递超过 5 个查询参数(组织的专有设置,应该不会传递),所以我想创建一个 EmployeeDto Class 并传递那个 class 在控制器

@GetMapping(value = "/employees", produces = {MediaType.APPLICATION_JSON })
public ResponseEntity<PagedModel<EmployeeModel>> findEmployees(
        EmployeeDto dto,
        @Parameter(hidden=true) String sort,
        @Parameter(hidden=true) String order,
        @Parameter(hidden=true) Pageable pageRequest) {

    // Add needed logic 
    ......
    ......
    ......
    PagedModel<EmployeeModel> model = employeePagedAssembler.toModel(response, employeeAssembler);

    return new ResponseEntity<>(model, HttpStatus.OK);
}

Swagger UI 它显示为 -

{
  "firstName": "string",
  "lastName": "string",
  "age": 0,
  "languageCd": "string",
  "isActive": "string",
  "email": "string",
  "regionCd": "string"
}

CURL 命令:

curl -X GET "http://localhost:8080/employee-data/employees/geographies?firstName=string&lastName=string&age=0&languageCd=string&isActive=string&email=string&regionCd=string&page=0&size=25&sort=firstName&order=ASC" -H "accept: application/json"

EmployeeDto.java

@AllArgsConstructor
@NoArgsConstructor
@Data
@Builder
@Schema
public class EmployeeDto {
    @Schema(description = AppConstants.FIRSTNAME, defaultValue="")
    private String firstName; 

    @Schema(description = AppConstants.LASTNAME, defaultValue="")
    private String lastName; 

    @Schema(description = AppConstants.AGE, defaultValue="")
    private Integer age; 

    @Schema(description = AppConstants.LANG_CD_DESC, defaultValue="0")
    private String languageCd;

    @Schema(description = AppConstants.ISACTIVE, defaultValue="")
    private String isActive; 

    @Schema(description = AppConstants.EMAIL, defaultValue="")
    private String email; 

    @Schema(description = AppConstants.REGION_CD_DESC, defaultValue="")
    private String regionCd;
}

我正在寻找 -

1) 如何为每个字段设置默认值而不是 "string" 似乎是默认值?

2) 如何简单地允许在 OAS3 中查看实际查询参数 UI?货币,看起来像 body.

我自己解决了这个问题。 example - Provides an example of the schema. When associated with a specific media type, the example string shall be parsed by the consumer to be treated as an object or an array.

代码 -

@AllArgsConstructor
@NoArgsConstructor
@Data
@Builder
@Schema
public class EmployeeDto {
    @Schema(description = AppConstants.FIRSTNAME, type = "string", example = " ")
    private String firstName; 

    @Schema(description = AppConstants.LASTNAME, type = "string", example = " ")
    private String lastName; 

    @Schema(description = AppConstants.AGE, type = "string", example = "null")
    private Integer age; 

    @Schema(description = AppConstants.LANG_CD_DESC, type = "string", example = " ")
    private String languageCd;

    @Schema(description = AppConstants.ISACTIVE, type = "string", example = " ")
    private String isActive; 

    @Schema(description = AppConstants.EMAIL, type = "string", example = " ")
    private String email; 

    @Schema(description = AppConstants.REGION_CD_DESC, type = "string", example = " ")
    private String regionCd;
}

并在控制器上简单地添加以下方法,如果发送了 "null" 值,该方法将重置,如果是,它将重置为 "" 并且对于 Integer 为 [=16] =].

public static Object getDefaulter(Object obj) {
    Arrays.stream(obj.getClass().getDeclaredFields()).map(f -> {
        f.setAccessible(true);
        try {
            // set null values only if found String value as "null"
            if (Objects.equals(f.get(obj), "null")) {
                f.set(obj, "");
            }else if(Objects.equals(f.get(obj), 0)) {
                f.set(obj, null);
            }
        } catch (IllegalArgumentException | IllegalAccessException e) {
            //
        }
        return f;
    }).collect(Collectors.toList());
    return obj;
}