如何从 OrderedDict 中提取特定值?

How do I extract specific values from an OrderedDict?

我喜欢提取特定的键并将它们存储到列表中。到目前为止,我能够从 MariaDB 读取并将行存储为字典(我更喜欢将输出作为 JSON):

import pymysql
import simplejson as json
import collections
import credentials_global

conn = pymysql.connect(
    host=credentials_global.mariadb_dev_ip_address,
    user=credentials_global.mariadb_dev_username,
    password=credentials_global.mariadb_dev_password,
    port=credentials_global.mariadb_dev_port,
    database=credentials_global.mariadb_dev_db_ticketing,
)

cursor = conn.cursor()
cursor.execute("select a, b, c, d, e, f from master.orders where c = 215")
rows = cursor.fetchall()

objects_list = []
for row in rows:
    d = collections.OrderedDict()
    d["a"] = row[0]
    d["b"] = row[1]
    d["c"] = row[2]
    d["d"] = row[3]
    d["e"] = row[4]
    d["f"] = row[5]
    objects_list.append(d)

j = json.dumps(objects_list)
print(j)

这会产生输出:

[
    {
        "a": 4153,
        "b": "NO_EFFECT",
        "c": "none",
        "d": "Medium",
        "e": 1,
        "f": "No Remarks",
    },
    {
        "a": 4154,
        "b": "SIGNIFICANT",
        "c": "none",
        "d": "Low",
        "e": 1,
        "f": "Test Message",
    },
]

我喜欢提取所有出现的 f。我试过:

for key, value in d.items():
    print(value)

这输出:

4153
NO_EFFECT
none
Medium
1
No Remarks

4154
SIGNIFICANT
none
Low
1
Test Message

我更喜欢只提取 f 以便输出类似于 [No Remarks, Test Message](我假设序列保持不变)。有人可以帮助我如何实现或在哪里寻找吗?

谢谢

for obj in objects_list:
    print(obj['f'])

OrderedDict 保留键的顺序 (a b c ...)。此输出中的顺序来自 objects_list.

中的顺序

将其添加到输出列表中:

only_f_fields = [ obj['f'] for obj in objects_list ]

我想你要找的答案是

for key, value in d.items():    
    print(value[0]['f'])

列表中的第一个元素 0,以及该列表中字典中的元素 f。

假设接收到的输出是一个列表:
ex = [{"a": 4153, "b": "NO_EFFECT", "c": "none", "d": "Medium", "e": 1, "f": "No Remarks"}, {"a": 4154, "b": "SIGNIFICANT", "c": "none", "d": "Low", "e": 1, "f": "Test Message"}]

我们可以执行两种方式,一种迭代通常不假设键顺序,另一种迭代顺序。

正常迭代检查(仅作说明)

f_list = list()
for val in ex:
    for k, v in val.items():
        if k == "f":
           f_list.append(v)

print(f_list)
输出:

['No Remarks', 'Test Message']

有序字典保持键的顺序:

f_list = list()
for val in ex:
    f_list.append(val["f"])
print(f_list)
输出:

['No Remarks', 'Test Message']