从不兼容的指针类型传递 fwrite 的参数 4

Question

我想将源文件的内容复制到目标文件，但是我得到这个警告：

warning: passing argument 4 of ‘fwrite’ from incompatible pointer type [-Wincompatible-pointer-types]

fwrite(target, sizeof(char), targetSize, sourceContent);

如果我忽略警告，则会出现分段错误。

FILE *source = fopen(argv[1], "r");
FILE *target = fopen(argv[2], "w");

if (source == NULL || target == NULL) {
    printf("One or both files do NOT exist\n");
    abort();
}

fseek(source, 0, SEEK_END);
long sourceSize = ftell(source);

fseek(source, 0, SEEK_SET);
char *sourceContent = (char *)malloc(sourceSize);
fread(sourceContent, sizeof(char), sourceSize, source);


long targetSize = sourceSize;
fwrite(target, sizeof(char), targetSize, sourceContent);

Answer 1

两个fread() and fwrite()都将read/write的缓冲区作为第一个参数，文件作为第四个参数。

// This is fine.
fread(sourceContent, sizeof(char), sourceSize, source);
// Swap the first and fourth argument in the fwrite call.
fwrite(sourceContent, sizeof(char), targetSize, target);

从不兼容的指针类型传递 fwrite 的参数 4

Passing argument 4 of fwrite from incompatible pointer type

c

fwrite

gcc-warning