如何使用带有 Python 的 Selenium 从列表中获取特定元素

How to get a specific element from a list using Selenium with Python

列表示例:

<div class="c-article-metrics-bar__wrapper u-clear-both">
      <ul class="c-article-metrics-bar u-list-inline">
         <li class="c-article-metrics-bar__item">
            <p class="c-article-metrics-bar__count">"277k "
              <span class="c-article-metrics-bar__label">Accesses</span>
            </p>
         </li> 
         <li class="c-article-metrics-bar__item">
            <p class="c-article-metrics-bar__count">"6 "
              <span class="c-article-metrics-bar__label">Citations</span>
            </p>
         </li>
         <li class="c-article-metrics-bar__item">
            <p class="c-article-metrics-bar__count">"594 "
              <span class="c-article-metrics-bar__label">Altmetric</span>
            </p>
         </li>
     </ul>
 </div>

我正在尝试从列表中获取 "Citations" 的计数。问题是,如果没有引用,列表元素将被省略。

我的想法是从 p 和 span 标签获取信息并将数据保存在两个列表中。然后遍历 span 标签列表,如果找到 "Citations" 字符串,则从 p 标签列表中该索引处的 return 文本,如下所示:

metrics_labels = self.wd.find_element_by_css_selector('span.c-article-metrics-bar__label')
labels = [label.text for label in metrics_labels]

metrics_counts = self.wd.find_element_by_css_selector('p.c-article-metrics-bar__count')
counts = [count.text for count in metrics_counts]

for i in range(len(labels) - 1):
  if labels[i] == "Citations":
    return counts[i]

但是它不起作用,我在这里缺少什么?

谢谢!

看起来你不是用 find_elements 收集所有元素,而是在这里使用 find_element 只收集 1 个:

metrics_labels = self.wd.find_element_by_css_selector('span.c-article-metrics-bar__label')

这里:

metrics_counts = self.wd.find_element_by_css_selector('p.c-article-metrics-bar__count')

要修复它,请尝试使用 find_elements_by_css_selector:

metrics_labels = self.wd.find_elements_by_css_selector('span.c-article-metrics-bar__label')
labels = [label.text for label in metrics_labels]

metrics_counts = self.wd.find_elements_by_css_selector('p.c-article-metrics-bar__count')
counts = [count.text for count in metrics_counts]

希望这能奏效,祝你好运!如果没有帮助,请告诉我们您遇到的错误。