已排序 Array/Map Swift

Question

我执行了一个 GET 请求，然后我将数据保存在 data 中，像这样

if let data: [MyMap] = response?.results {
   let var_to_sort = data
   self.generateStuff(var: var_to_sort)
}

MyMap 是这样定义的可映射对象：

class MyMap: NSCoding {
   var name: String?
   var score: Score?
   ...

使用映射、编码等... 分数同上：

class Score:NSCoding {
   var number: Double?
   ...

我需要的是根据数量（从大到小）对var_to_sort = data进行排序并传递到 generateStuff 方法。请记住 response.results 有不止 1 个对象。有人可以帮助我吗？

Answer 1

只需对数组进行排序：

let var_to_sort = data.sorted {
  [=10=].score?.number ?? 0 > .score?.number ?? 0
}

Answer 2

我确实有适合您需要的可行解决方案。并且可能是一种通过在不需要时尝试避免可选项来改进代码的方法。如果您的网络服务总是 return 对象的名称和分数，那么请不要使用可选值，这会让您的生活更轻松。您可以在我的解决方案中看到，当我没有任何可选代码时，代码更易于阅读，而且这样的操作也很简单。

// -------------- Solution 1 avoiding optionals ----------------

struct MyObject {
    var name: String
    var score: Score
}

struct Score {
    var number: Double
}

let data: [MyObject] = [MyObject(name: "obj1", score: Score(number: 12)),
                        MyObject(name: "obj2", score: Score(number: 2)),
                        MyObject(name: "obj3", score: Score(number: 24)),
                        MyObject(name: "obj4", score: Score(number: 4)),
                        MyObject(name: "obj5", score: Score(number: 1))]

let sortedObj = data.sorted(by: { [=10=].score.number > .score.number })
print(sortedObj)
// Print: obj3, obj1, obj4, obj2 and obj5

// -------------- Solution 2 using optionals ----------------

struct MyObject2 {
    var name: String?
    var score: Score2?
}

struct Score2 {
    var number: Double?
}

let data2: [MyObject2] = [MyObject2(name: "obj1", score: Score2(number: 12)),
                          MyObject2(name: "obj2", score: Score2(number: 2)),
                          MyObject2(name: "obj3", score: Score2(number: 24)),
                          MyObject2(name: "obj4", score: Score2(number: 4)),
                          MyObject2(name: "obj5", score: Score2(number: 1))]

let sortedObj2 = data2.sorted(by: {
    guard let num1 = [=10=].score?.number, let num2 = .score?.number else {
        return false
    }
    return num1 > num2
})
print(sortedObj2)
// Print: obj3, obj1, obj4, obj2 and obj5

希望对您有所帮助

Answer 3

按此方式对数组进行排序。

data2.sort(by:{[=10=].score?.number > .score?.number})

已排序 Array/Map Swift

Sorted Array/Map Swift

ios

swift

xcode

sorting

nscoding