为什么 C struct tm (time.h) 返回错误的月份？

Question

目前是 2020 年 4 月 10 日。我在 C 中制作了这个整数月到字符串月的转换器函数。它接受一个整数和 returns 一个字符串。出于某种原因，它认为现在是 3 月。我调查了问题是我的转换器还是其他问题我打印了 myTime->tm_mon 并且它 returned 2 （三月）当它应该 return 3 （四月）。谁能找到（我假设是）我的错误并指出给我？

#include <stdio.h>
#include <stdlib.h>
#include <time.h>

typedef struct tm tm;

void *numberToLetters(int month) {
    char *smonth;
    switch (month) {
    case (0):
        smonth = "January";
        break;
    case (1):
        smonth = "February";
        break;
    case (2):
        smonth = "March";
        break;
    case (3):
        smonth = "April";
        break;
    case (4):
        smonth = "May";
        break;
    case (5):
        smonth = "June";
        break;
    case (6):
        smonth = "July";
        break;
    case (7):
        smonth = "August";
        break;
    case (8):
        smonth = "September";
        break;
    case (9):
        smonth = "October";
        break;
    case (10):
        smonth = "November";
        break;
    case (11):
        smonth = "December";
        break;
    default:
        return NULL;
    }
    return smonth;
}

int main() {
    time_t present;
    time(&present);
    tm *myTime = &present;
    void *month = (char *)numberToLetters(myTime->tm_mon);
    printf("%s\n", month);
    return 0;
}

Answer 1

time() returns time_t, to convert it to tm structure, you can use localtime()

改为

tm *myTime = localtime(&present);

并打印四月

为什么 C struct tm (time.h) 返回错误的月份？

Why is C struct tm (time.h) returning the wrong month?

c

time

ctime