根据另一行中的条件构建总计
Building totals based on condition in another row
真的很难理解这样做的最佳方法...
我有一个table的数据
**StudentID AssessmentCode ResultGroup Result**
46933 12ENG IBLevel HL
46933 12ENG Mark 6
46933 12ECO IBLevel HL
46933 12ECO Mark 5
46933 12GEO IBLevel SL
46933 12GEO Mark 6
46933 12LAN IBLevel HL
46933 12LAN Mark 4
46933 12PED IBLevel SL
46933 12PED Mark 5
46933 12SCI IBLevel SL
46933 12SCI Mark 3
67767 12FRE IBLevel HL
67767 12FRE Mark 4
67767 12MAT IBLevel SL
67767 12MAT Mark 5
and so on...
不幸的是，结果列包含 2 位不同的信息。学生的水平（HL = 高水平；SL = 标准水平），然后是该科目在该水平的成绩。请注意，对于每个学生，每个学生的每个科目都会生成 2 行，一行包含 IBLevel，下一行包含该级别的结果。
如何重新排列数据以获得类似
的内容
StudentID HLResult SLResult TotalResult CountofHL CountofSL
46933 15 14 29 3 3
67767 13 10 23 4 2
所以每个学生都有一行数据，其中包含 HL、SL 的总计，以及 HL 和 SL 科目的数量。正如我所说，真的不确定解决这个问题的最佳方法。最后，我还想扩展它以获得一些列，这些列根据结果给出一些警告消息，例如 TotalResult 必须大于 24，所以我喜欢一个列，它只是 returns 是否有是否实现...
StudentID HLResult SLResult TotalResult CountofHL CountofSL MoreThan24
46933 15 14 29 3 3 True
67767 13 10 23 4 2 False
任何帮助将不胜感激...
您的 table 似乎存在一些严重的规范化问题。您必须先在 AssessmentCode 上执行 INNER JOIN：
SELECT t1.StudentID, t1.AssessmentCode,
t1.Result AS Level, CAST(t2.Result AS INT) AS Mark
FROM (
SELECT StudentID, AssessmentCode, Result
FROM mytable
WHERE ResultGroup = 'IBLevel' ) AS t1
INNER JOIN (
SELECT StudentID, AssessmentCode, Result
FROM mytable
WHERE ResultGroup = 'Mark' ) AS t2
ON t1.StudentID = t2.StudentID AND t1.AssessmentCode = t2.AssessmentCode
每 AssessmentCode 获得一行。
输出：
StudentID AssessmentCode Level Mark
-----------------------------------------
46933 12ENG HL 6
46933 12ECO HL 5
46933 12GEO SL 6
46933 12LAN HL 4
46933 12PED SL 5
46933 12SCI SL 3
67767 12FRE HL 4
67767 12MAT SL 5
您现在可以将上述查询包装在 CTE 中并执行 条件聚合 以获得所需的结果：
;WITH CTE AS (
... above query here
)
SELECT StudentID,
SUM(CASE WHEN Level = 'HL' THEN Mark ELSE 0 END) AS HLResult,
SUM(CASE WHEN Level = 'SL' THEN Mark ELSE 0 END) AS SLResult,
SUM(Mark) AS TotalResult,
COUNT(CASE WHEN Level = 'HL' THEN 1 END) AS CountofHL,
COUNT(CASE WHEN Level = 'SL' THEN 1 END) AS CountofSL,
CASE WHEN SUM(Mark) > 24 THEN 'True'
ELSE 'False'
END AS MoreThan24
FROM CTE
GROUP BY StudentID
输出：
StudentID HLResult SLResult TotalResult CountofHL CountofSL MoreThan24
46933 15 14 29 3 3 True
67767 4 5 9 1 1 False
你的我的版本Table
DECLARE @yourTable TABLE
(
StudentID INT,
AssessmentCode CHAR(5),
ResultGroup VARCHAR(10),
Result VARCHAR(5)
)
INSERT INTO @yourTable
VALUES (46933,'12ENG','IBLevel','HL'),
(46933,'12ENG','Mark','6'),
(46933,'12ECO','IBLevel','HL'),
(46933,'12ECO','Mark','5'),
(46933,'12GEO','IBLevel','SL'),
(46933,'12GEO','Mark','6'),
(46933,'12LAN','IBLevel','HL'),
(46933,'12LAN','Mark','4'),
(46933,'12PED','IBLevel','SL'),
(46933,'12PED','Mark','5'),
(46933,'12SCI','IBLevel','SL'),
(46933,'12SCI','Mark','3'),
(67767,'12FRE','IBLevel','HL'),
(67767,'12FRE','Mark','4'),
(67767,'12MAT','IBLevel','SL'),
(67767,'12MAT','Mark','5');
实际查询
WITH CTE_ResultValue
AS
(
SELECT StudentID,
AssessmentCode,
ResultGroup,
CAST(Result AS INT) AS ResultValue
FROM @yourTable
WHERE ISNUMERIC(Result) = 1
),
CTE_IBLevel
AS
(
SELECT StudentID,
AssessmentCode,
Result AS IBLevel
FROM @yourTable
WHERE ISNUMERIC(Result) = 0
),
CTE_Normalized
AS
(
SELECT A.StudentID,
A.AssessmentCode,
A.ResultGroup,
A.ResultValue,
B.IBLevel
FROM CTE_ResultValue AS A
INNER JOIN CTE_IBLevel AS B
ON A.StudentID = B.StudentID
AND A.AssessmentCode = B.AssessmentCode
)
SELECT [StudentID],
[HLResult] = SUM(CASE WHEN IBLevel = 'HL' THEN ResultValue END),
[SLResult] = SUM(CASE WHEN IBLevel = 'SL' THEN ResultValue END),
[TotalResult] = SUM(ResultValue),
[CountOfHL] = SUM(CASE WHEN IBLevel = 'HL' THEN 1 END),
[CountOfSL] = SUM(CASE WHEN IBLevel = 'SL' THEN 1 END)
FROM CTE_Normalized
GROUP BY StudentID
规范化
您的 table 非常需要规范化。如果您可以更改它，最小的更改将如下所示：
CREATE TABLE dbo.NormalizedTable
(
StudentID INT,
AssessmentCode CHAR(5),
ResultGroup VARCHAR(25),
ResultValue SMALLINT, --smallint range should be plenty. It can store values from -32,768 to 32,767
IBLevel CHAR(2)
)
INSERT INTO dbo.NormalizedTable
SELECT *
FROM CTE_Normalized
如果您无法更改数据的结构方式，我建议您从我的 CTE_normalized
创建一个视图
CREATE VIEW vw_normalizedTable
AS
WITH CTE_ResultValue
AS
(
SELECT StudentID,
AssessmentCode,
ResultGroup,
CAST(Result AS INT) AS ResultValue
FROM @yourTable
WHERE ISNUMERIC(Result) = 1
),
CTE_IBLevel
AS
(
SELECT StudentID,
AssessmentCode,
Result AS IBLevel
FROM @yourTable
WHERE ISNUMERIC(Result) = 0
),
SELECT A.StudentID,
A.AssessmentCode,
A.ResultGroup,
A.ResultValue,
B.IBLevel
FROM CTE_ResultValue AS A
INNER JOIN CTE_IBLevel AS B
ON A.StudentID = B.StudentID
AND A.AssessmentCode = B.AssessmentCode
GO
版本 1:
SELECT t1.StudentID,
SUM(CASE WHEN t1.Result = 'HL' THEN t2.Result ELSE 0 END) HLResult,
SUM(CASE WHEN t1.Result = 'SL' THEN t2.Result ELSE 0 END) SLResult,
SUM(CAST(t2.Result AS INT)) TotalResult,
SUM(CASE WHEN t1.Result = 'HL' THEN 1 ELSE 0 END) CountofHL,
SUM(CASE WHEN t1.Result = 'SL' THEN 1 ELSE 0 END) CountofSL,
CASE WHEN SUM(CAST(t2.Result AS INT)) > 24 THEN 'True' ELSE 'False' END MoreThan24
FROM @t t1
JOIN @t t2 ON t1.StudentID = t2.StudentID AND
t1.AssessmentCode = t2.AssessmentCode AND
t1.ResultGroup = 'IBLevel' AND
t2.ResultGroup = 'Mark'
GROUP BY t1.StudentID
版本 2：
WITH cte1 AS(
SELECT *, ROW_NUMBER() OVER(PARTITION BY StudentID, AssessmentCode
ORDER BY CASE WHEN ResultGroup = 'IBLevel' THEN 1 ELSE 2 END) AS rn FROM @t),
cte2 AS(SELECT StudentID,
AssessmentCode,
SUM(CASE WHEN Result = 'HL' THEN 1 ELSE 0 END) HL,
SUM(CASE WHEN Result = 'SL' THEN 1 ELSE 0 END) SL,
MAX(CASE WHEN rn = 2 THEN Result END) R
FROM cte1
GROUP BY StudentID, AssessmentCode)
SELECT StudentID,
SUM(hl*R) HLResult,
SUM(sl*R) SLResult,
SUM((hl + sl)*r) TotalResult,
SUM(hl) CountofHL,
SUM(sl) CountofSL,
CASE WHEN SUM((hl + sl)*r) > 24 THEN 'True' ELSE 'False' END MoreThan24
FROM cte2
GROUP BY StudentID
输出：
StudentID HLResult SLResult TotalResult CountofHL CountofSL MoreThan24
46933 15 14 29 3 3 True
67767 4 5 9 1 1 False
只需将 @t 替换为您的 table。
真的很难理解这样做的最佳方法...
我有一个table的数据
**StudentID AssessmentCode ResultGroup Result**
46933 12ENG IBLevel HL
46933 12ENG Mark 6
46933 12ECO IBLevel HL
46933 12ECO Mark 5
46933 12GEO IBLevel SL
46933 12GEO Mark 6
46933 12LAN IBLevel HL
46933 12LAN Mark 4
46933 12PED IBLevel SL
46933 12PED Mark 5
46933 12SCI IBLevel SL
46933 12SCI Mark 3
67767 12FRE IBLevel HL
67767 12FRE Mark 4
67767 12MAT IBLevel SL
67767 12MAT Mark 5
and so on...
不幸的是，结果列包含 2 位不同的信息。学生的水平（HL = 高水平；SL = 标准水平），然后是该科目在该水平的成绩。请注意，对于每个学生，每个学生的每个科目都会生成 2 行，一行包含 IBLevel，下一行包含该级别的结果。
如何重新排列数据以获得类似
的内容StudentID HLResult SLResult TotalResult CountofHL CountofSL
46933 15 14 29 3 3
67767 13 10 23 4 2
所以每个学生都有一行数据，其中包含 HL、SL 的总计，以及 HL 和 SL 科目的数量。正如我所说，真的不确定解决这个问题的最佳方法。最后，我还想扩展它以获得一些列，这些列根据结果给出一些警告消息，例如 TotalResult 必须大于 24，所以我喜欢一个列，它只是 returns 是否有是否实现...
StudentID HLResult SLResult TotalResult CountofHL CountofSL MoreThan24
46933 15 14 29 3 3 True
67767 13 10 23 4 2 False
任何帮助将不胜感激...
您的 table 似乎存在一些严重的规范化问题。您必须先在 AssessmentCode 上执行 INNER JOIN：
SELECT t1.StudentID, t1.AssessmentCode,
t1.Result AS Level, CAST(t2.Result AS INT) AS Mark
FROM (
SELECT StudentID, AssessmentCode, Result
FROM mytable
WHERE ResultGroup = 'IBLevel' ) AS t1
INNER JOIN (
SELECT StudentID, AssessmentCode, Result
FROM mytable
WHERE ResultGroup = 'Mark' ) AS t2
ON t1.StudentID = t2.StudentID AND t1.AssessmentCode = t2.AssessmentCode
每 AssessmentCode 获得一行。
输出：
StudentID AssessmentCode Level Mark
-----------------------------------------
46933 12ENG HL 6
46933 12ECO HL 5
46933 12GEO SL 6
46933 12LAN HL 4
46933 12PED SL 5
46933 12SCI SL 3
67767 12FRE HL 4
67767 12MAT SL 5
您现在可以将上述查询包装在 CTE 中并执行 条件聚合 以获得所需的结果：
;WITH CTE AS (
... above query here
)
SELECT StudentID,
SUM(CASE WHEN Level = 'HL' THEN Mark ELSE 0 END) AS HLResult,
SUM(CASE WHEN Level = 'SL' THEN Mark ELSE 0 END) AS SLResult,
SUM(Mark) AS TotalResult,
COUNT(CASE WHEN Level = 'HL' THEN 1 END) AS CountofHL,
COUNT(CASE WHEN Level = 'SL' THEN 1 END) AS CountofSL,
CASE WHEN SUM(Mark) > 24 THEN 'True'
ELSE 'False'
END AS MoreThan24
FROM CTE
GROUP BY StudentID
输出：
StudentID HLResult SLResult TotalResult CountofHL CountofSL MoreThan24
46933 15 14 29 3 3 True
67767 4 5 9 1 1 False
你的我的版本Table
DECLARE @yourTable TABLE
(
StudentID INT,
AssessmentCode CHAR(5),
ResultGroup VARCHAR(10),
Result VARCHAR(5)
)
INSERT INTO @yourTable
VALUES (46933,'12ENG','IBLevel','HL'),
(46933,'12ENG','Mark','6'),
(46933,'12ECO','IBLevel','HL'),
(46933,'12ECO','Mark','5'),
(46933,'12GEO','IBLevel','SL'),
(46933,'12GEO','Mark','6'),
(46933,'12LAN','IBLevel','HL'),
(46933,'12LAN','Mark','4'),
(46933,'12PED','IBLevel','SL'),
(46933,'12PED','Mark','5'),
(46933,'12SCI','IBLevel','SL'),
(46933,'12SCI','Mark','3'),
(67767,'12FRE','IBLevel','HL'),
(67767,'12FRE','Mark','4'),
(67767,'12MAT','IBLevel','SL'),
(67767,'12MAT','Mark','5');
实际查询
WITH CTE_ResultValue
AS
(
SELECT StudentID,
AssessmentCode,
ResultGroup,
CAST(Result AS INT) AS ResultValue
FROM @yourTable
WHERE ISNUMERIC(Result) = 1
),
CTE_IBLevel
AS
(
SELECT StudentID,
AssessmentCode,
Result AS IBLevel
FROM @yourTable
WHERE ISNUMERIC(Result) = 0
),
CTE_Normalized
AS
(
SELECT A.StudentID,
A.AssessmentCode,
A.ResultGroup,
A.ResultValue,
B.IBLevel
FROM CTE_ResultValue AS A
INNER JOIN CTE_IBLevel AS B
ON A.StudentID = B.StudentID
AND A.AssessmentCode = B.AssessmentCode
)
SELECT [StudentID],
[HLResult] = SUM(CASE WHEN IBLevel = 'HL' THEN ResultValue END),
[SLResult] = SUM(CASE WHEN IBLevel = 'SL' THEN ResultValue END),
[TotalResult] = SUM(ResultValue),
[CountOfHL] = SUM(CASE WHEN IBLevel = 'HL' THEN 1 END),
[CountOfSL] = SUM(CASE WHEN IBLevel = 'SL' THEN 1 END)
FROM CTE_Normalized
GROUP BY StudentID
规范化
您的 table 非常需要规范化。如果您可以更改它，最小的更改将如下所示：
CREATE TABLE dbo.NormalizedTable
(
StudentID INT,
AssessmentCode CHAR(5),
ResultGroup VARCHAR(25),
ResultValue SMALLINT, --smallint range should be plenty. It can store values from -32,768 to 32,767
IBLevel CHAR(2)
)
INSERT INTO dbo.NormalizedTable
SELECT *
FROM CTE_Normalized
如果您无法更改数据的结构方式，我建议您从我的 CTE_normalized
创建一个视图CREATE VIEW vw_normalizedTable
AS
WITH CTE_ResultValue
AS
(
SELECT StudentID,
AssessmentCode,
ResultGroup,
CAST(Result AS INT) AS ResultValue
FROM @yourTable
WHERE ISNUMERIC(Result) = 1
),
CTE_IBLevel
AS
(
SELECT StudentID,
AssessmentCode,
Result AS IBLevel
FROM @yourTable
WHERE ISNUMERIC(Result) = 0
),
SELECT A.StudentID,
A.AssessmentCode,
A.ResultGroup,
A.ResultValue,
B.IBLevel
FROM CTE_ResultValue AS A
INNER JOIN CTE_IBLevel AS B
ON A.StudentID = B.StudentID
AND A.AssessmentCode = B.AssessmentCode
GO
版本 1:
SELECT t1.StudentID,
SUM(CASE WHEN t1.Result = 'HL' THEN t2.Result ELSE 0 END) HLResult,
SUM(CASE WHEN t1.Result = 'SL' THEN t2.Result ELSE 0 END) SLResult,
SUM(CAST(t2.Result AS INT)) TotalResult,
SUM(CASE WHEN t1.Result = 'HL' THEN 1 ELSE 0 END) CountofHL,
SUM(CASE WHEN t1.Result = 'SL' THEN 1 ELSE 0 END) CountofSL,
CASE WHEN SUM(CAST(t2.Result AS INT)) > 24 THEN 'True' ELSE 'False' END MoreThan24
FROM @t t1
JOIN @t t2 ON t1.StudentID = t2.StudentID AND
t1.AssessmentCode = t2.AssessmentCode AND
t1.ResultGroup = 'IBLevel' AND
t2.ResultGroup = 'Mark'
GROUP BY t1.StudentID
版本 2：
WITH cte1 AS(
SELECT *, ROW_NUMBER() OVER(PARTITION BY StudentID, AssessmentCode
ORDER BY CASE WHEN ResultGroup = 'IBLevel' THEN 1 ELSE 2 END) AS rn FROM @t),
cte2 AS(SELECT StudentID,
AssessmentCode,
SUM(CASE WHEN Result = 'HL' THEN 1 ELSE 0 END) HL,
SUM(CASE WHEN Result = 'SL' THEN 1 ELSE 0 END) SL,
MAX(CASE WHEN rn = 2 THEN Result END) R
FROM cte1
GROUP BY StudentID, AssessmentCode)
SELECT StudentID,
SUM(hl*R) HLResult,
SUM(sl*R) SLResult,
SUM((hl + sl)*r) TotalResult,
SUM(hl) CountofHL,
SUM(sl) CountofSL,
CASE WHEN SUM((hl + sl)*r) > 24 THEN 'True' ELSE 'False' END MoreThan24
FROM cte2
GROUP BY StudentID
输出：
StudentID HLResult SLResult TotalResult CountofHL CountofSL MoreThan24
46933 15 14 29 3 3 True
67767 4 5 9 1 1 False
只需将 @t 替换为您的 table。