MySQL select 并计算 2 个具有不同 where 子句的列

Question

我觉得应该很容易，但是根本就不行。我有一个 table，我想生成一个显示分组项目的图表，其中一个 where 子句（第 1 列）应该显示状态为 0 的条目，而另一个 where 子句（第 2 列）应该显示显示状态为 1 的条目。

如果我只执行一个查询，它工作正常，但我想在一个组合查询中同时拥有这两个（状态 0 和状态 1）。

状态 0 查询：

SELECT item,quantity, COUNT(status) FROM `table` 
WHERE `retry` = 1
AND `status` = 0
GROUP BY item,quantity
ORDER BY COUNT(status) DESC

状态 1 查询：

SELECT item,quantity, COUNT(status) FROM `table` 
WHERE `retry` = 1
AND `status` = 1
GROUP BY item,quantity
ORDER BY COUNT(status) DESC

我尝试将两者结合起来（没用）

SELECT t1.item,t1.quantity, COUNT(t2.status), COUNT(t3.status) FROM `table` AS t1
LEFT JOIN (SELECT item,status FROM `table` WHERE `status` = '0' AND `retry` = 1 GROUP BY item,quantity) AS t2
ON t1.ndc = t2.ndc
LEFT JOIN (SELECT item,status FROM `table` WHERE `status` = '1' AND `retry` = 1 GROUP BY item,quantity) AS t3
ON t1.ndc = t3.ndc
WHERE 1
GROUP BY t1.item,t1.quantity
ORDER BY COUNT(t2.status) DESC

Answer 1

请检查这个，它对你有用吗？

请试试这个

 SELECT
    item,quantity,
    COUNT(case when status =1 then 1 end) AS status1,
    COUNT(case when status =0 then 1 end) AS status0
  FROM table

Answer 2

h=12=hh=14=hh=13=hh 测试日期：h=11=hh w=10=sh

MySQL select 并计算 2 个具有不同 where 子句的列

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