是什么导致我的条件 [Python] 出现缩进错误
What is causing an Indentation error in my conditionals [Python]
所以,我有这段代码,其中我通过 IF 语句比较了五张图片(不要介意那部分代码,我只是想给你们一些上下文)但是我得到了一个缩进他们内部的错误,我无法解决它。我只是看不出我的错误,我需要第二个意见:(
import cv2
width=50
height=50
dimension = (width,height)
img1 = cv2.cv2.imread('D:/Scripts/img/CAPTCHA/Imagen_0.png',cv2.cv2.IMREAD_GRAYSCALE)
img2 = cv2.cv2.imread('D:/Scripts/img/CAPTCHA/Imagen_1.png',cv2.cv2.IMREAD_GRAYSCALE)
img3 = cv2.cv2.imread('D:/Scripts/img/CAPTCHA/Imagen_2.png',cv2.cv2.IMREAD_GRAYSCALE)
img4 = cv2.cv2.imread('D:/Scripts/img/CAPTCHA/Imagen_3.png',cv2.cv2.IMREAD_GRAYSCALE)
img5 = cv2.cv2.imread('D:/Scripts/img/CAPTCHA/Imagen_4.png',cv2.cv2.IMREAD_GRAYSCALE)
img1 = cv2.cv2.resize(img1,dimension,interpolation=cv2.cv2.INTER_AREA)
img2 = cv2.cv2.resize(img2,dimension,interpolation=cv2.cv2.INTER_AREA)
img3 = cv2.cv2.resize(img3,dimension,interpolation=cv2.cv2.INTER_AREA)
img4 = cv2.cv2.resize(img4,dimension,interpolation=cv2.cv2.INTER_AREA)
img5 = cv2.cv2.resize(img5,dimension,interpolation=cv2.cv2.INTER_AREA)
if cv2.cv2.countNonZero(img1[0]) != cv2.cv2.countNonZero(img2[0]):
if cv2.cv2.countNonZero(img1[0]) == cv2.cv2.countNonZero(img3[0]):
#search image 2
else:
#search image 1
else:
if cv2.cv2.countNonZero(img1[0]) != cv2.cv2.countNonZero(img3[0]):
if cv2.cv2.countNonZero(img1[0]) == cv2.cv2.countNonZero(img4[0]):
#search image 3
else:
#no image found
else:
if cv2.cv2.countNonZero(img1[0]) != cv2.cv2.countNonZero(img4[0]):
if cv2.cv2.countNonZero(img1[0]) == cv2.cv2.countNonZero(img5[0]):
#search image 4
else:
#search image 5
请帮助我处理 IF 语句结构,不用担心其余代码:( 我只需要解决缩进问题。
您需要在每个条件语句中包含某种有效代码。使用 pass
作为占位符,直到您准备好在那里编写一些代码:
if cv2.cv2.countNonZero(img1[0]) != cv2.cv2.countNonZero(img2[0]):
if cv2.cv2.countNonZero(img1[0]) == cv2.cv2.countNonZero(img3[0]):
#search image 2
pass
else:
#search image 1
pass
else:
if cv2.cv2.countNonZero(img1[0]) != cv2.cv2.countNonZero(img3[0]):
if cv2.cv2.countNonZero(img1[0]) == cv2.cv2.countNonZero(img4[0]):
#search image 3
pass
else:
#no image found
pass
else:
if cv2.cv2.countNonZero(img1[0]) != cv2.cv2.countNonZero(img4[0]):
if cv2.cv2.countNonZero(img1[0]) == cv2.cv2.countNonZero(img5[0]):
#search image 4
pass
else:
pass
#search image 5
关于 pass
的一些额外阅读:
https://www.programiz.com/python-programming/pass-statement
https://www.educative.io/edpresso/what-is-pass-statement-in-python
https://www.w3schools.com/python/ref_keyword_pass.asp
How to use the pass statement?
https://www.geeksforgeeks.org/break-continue-and-pass-in-python/
所以,我有这段代码,其中我通过 IF 语句比较了五张图片(不要介意那部分代码,我只是想给你们一些上下文)但是我得到了一个缩进他们内部的错误,我无法解决它。我只是看不出我的错误,我需要第二个意见:(
import cv2
width=50
height=50
dimension = (width,height)
img1 = cv2.cv2.imread('D:/Scripts/img/CAPTCHA/Imagen_0.png',cv2.cv2.IMREAD_GRAYSCALE)
img2 = cv2.cv2.imread('D:/Scripts/img/CAPTCHA/Imagen_1.png',cv2.cv2.IMREAD_GRAYSCALE)
img3 = cv2.cv2.imread('D:/Scripts/img/CAPTCHA/Imagen_2.png',cv2.cv2.IMREAD_GRAYSCALE)
img4 = cv2.cv2.imread('D:/Scripts/img/CAPTCHA/Imagen_3.png',cv2.cv2.IMREAD_GRAYSCALE)
img5 = cv2.cv2.imread('D:/Scripts/img/CAPTCHA/Imagen_4.png',cv2.cv2.IMREAD_GRAYSCALE)
img1 = cv2.cv2.resize(img1,dimension,interpolation=cv2.cv2.INTER_AREA)
img2 = cv2.cv2.resize(img2,dimension,interpolation=cv2.cv2.INTER_AREA)
img3 = cv2.cv2.resize(img3,dimension,interpolation=cv2.cv2.INTER_AREA)
img4 = cv2.cv2.resize(img4,dimension,interpolation=cv2.cv2.INTER_AREA)
img5 = cv2.cv2.resize(img5,dimension,interpolation=cv2.cv2.INTER_AREA)
if cv2.cv2.countNonZero(img1[0]) != cv2.cv2.countNonZero(img2[0]):
if cv2.cv2.countNonZero(img1[0]) == cv2.cv2.countNonZero(img3[0]):
#search image 2
else:
#search image 1
else:
if cv2.cv2.countNonZero(img1[0]) != cv2.cv2.countNonZero(img3[0]):
if cv2.cv2.countNonZero(img1[0]) == cv2.cv2.countNonZero(img4[0]):
#search image 3
else:
#no image found
else:
if cv2.cv2.countNonZero(img1[0]) != cv2.cv2.countNonZero(img4[0]):
if cv2.cv2.countNonZero(img1[0]) == cv2.cv2.countNonZero(img5[0]):
#search image 4
else:
#search image 5
请帮助我处理 IF 语句结构,不用担心其余代码:( 我只需要解决缩进问题。
您需要在每个条件语句中包含某种有效代码。使用 pass
作为占位符,直到您准备好在那里编写一些代码:
if cv2.cv2.countNonZero(img1[0]) != cv2.cv2.countNonZero(img2[0]):
if cv2.cv2.countNonZero(img1[0]) == cv2.cv2.countNonZero(img3[0]):
#search image 2
pass
else:
#search image 1
pass
else:
if cv2.cv2.countNonZero(img1[0]) != cv2.cv2.countNonZero(img3[0]):
if cv2.cv2.countNonZero(img1[0]) == cv2.cv2.countNonZero(img4[0]):
#search image 3
pass
else:
#no image found
pass
else:
if cv2.cv2.countNonZero(img1[0]) != cv2.cv2.countNonZero(img4[0]):
if cv2.cv2.countNonZero(img1[0]) == cv2.cv2.countNonZero(img5[0]):
#search image 4
pass
else:
pass
#search image 5
关于 pass
的一些额外阅读:
https://www.programiz.com/python-programming/pass-statement
https://www.educative.io/edpresso/what-is-pass-statement-in-python
https://www.w3schools.com/python/ref_keyword_pass.asp
How to use the pass statement?
https://www.geeksforgeeks.org/break-continue-and-pass-in-python/