Laravel 6 l “从空值创建默认对象”

Question

在这里，我设置了 CRUD table 与 laravel、vuetify 和 vue 。我可以成功地从数据库中创建和读取数据。但是，由于某种原因，我的更新和删除不起作用。我收到如下错误：

{消息："Creating default object from empty value"，异常："ErrorException"，…} 异常："ErrorException" 文件："C:\WinNMP\WWW\chillibiz\app\Sys\Http\Controllers\StageController.php" 行：53 消息："Creating default object from empty value" 跟踪：[{文件："C:\WinNMP\WWW\chillibiz\app\Sys\Http\Controllers\StageController.php"，行：53，…}，…]

我的代码在这里：

StageController.php

<?php


namespace App\Sys\Http\Controllers;

use App\Http\Controllers\Controller;

use Illuminate\Http\Request;

use Illuminate\Support\Str;

use App\Sys\Model\Stage;

class StageController extends Controller
{

    public function index(Request $request)
    {  
        $per_page = $request->per_page ? $request->per_page : 5;
        $sort_by = $request->sort_by;
        $order_by = $request->order_by;
        return response()->json(['stages' => Stage::orderBy($sort_by, $order_by)->paginate($per_page)],200);
    }

    public function store(Request $request)
    {
        $uuid = Str::uuid()->toString();
        $stage= Stage::create([
            'id' => $uuid,
            'code' =>$request->code,
            'name' =>$request->name,
            'description' =>$request->description,
        ]);
        return response()->json(['stage'=>$stage],200);
    }


    public function show($id)                                                                                                                                                           
    {
        $stages = Stage::where('code','LIKE', "%$id%")->orWhere('name','LIKE', "%$id%")->orWhere('description', 'LIKE', "%$id%")->paginate();
        return response()->json(['stages' => $stages],200);
    }



    public function update(Request $request, $id)
    {


       $stage = Stage::find($id);


       $stage->code  = $request->code; //line 53
       $stage->name  = $request->name;
       $stage->description  = $request->description;


       $stage->save(); 
       return response()->json(['stage'=>$stage], 200);
    }

    public function destroy($id)
    {
        $stage = Stage::where('id', $id)->delete();
        return  response()->json(['stage'=> $stage],200);
    }



    public function deleteAll(Request $request){
        Stage::whereIn('id', $request->stages)->delete();
        return response()->json(['message', 'Records Deleted Successfully'], 200);
    }
}

Stage.php

<?php

namespace App\Sys\Model;

use Illuminate\Database\Eloquent\Model;

class Stage extends Model
{
    protected $guarded = [];
}

Answer 1

我刚刚发现他们使用 uuid 作为 id 而不是递增。这就是为什么你会得到这样的错误：

要解决您的问题，您需要将该字段添加到您的模型中；

<?php

namespace App\Sys\Model;

use Illuminate\Database\Eloquent\Model;

class Stage extends Model
{
    public $incrementing = false;
    protected $keyType = 'string';
    protected $guarded = [];

}

希望这次能解决您的问题。快乐的编码。编辑你可以阅读 docs for more info

Laravel 6 l “从空值创建默认对象”

Larave 6 l “Creating default object from empty value”

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