用帧计算两个音频持续时间

Calculate two audio duration with frame

卡住了,需要一个小逻辑

我有两个音频时长

x = "00:00:07:18"
y = "00:00:06:00"        H : M: S: F  
Answer should be x + y = 00:00:13:18 

H=小时 S=秒 M=分钟 F=帧

我的问题是

if x = "00:00:03:14"
   y = "00:00:13:18"

answer should be x + y = **00:00:17:02**

如果帧数大于 30,则应以秒为单位增加 1。

我正在用电shell。如何确定计算这两者的逻辑?

前3部分(hour:minute:second)的计算,我们可以卸载到[timespan]类型,那么我们只需要担心将多余的帧带过来:

# Simple helper function to turn our input strings into a [timespan] + frame count
function Parse-FrameDuration
{
    param(
        [string]$Duration
    )

    $hour,$minute,$second,$frame = ($Duration -split ':') -as [int[]]

    [PSCustomObject]@{
        Time = New-TimeSpan -Hours $hour -Minutes $minute -Seconds $second
        Frame = $frame
    }
}

# function to do the actual calculation
function Add-Frame
{
    param(
        [string]$Base,
        [string]$Offset
    )

    # Parse our two timestamps
    $a = Parse-FrameDuration $Base
    $b = Parse-FrameDuration $Offset

    # Calculate frames % frame rate, remember to carry any excess seconds
    $frames = 0
    $carry = [math]::DivRem($a.Frame + $b.Frame , 30, [ref]$frames)

    # Calculate time difference, add any extra second carried from frame count
    $new = ($a.Time + $b.Time).Add($(New-TimeSpan -Seconds $carry))

    # Stitch output string together from new timespan + remaining frames
    return "{0:hh\:mm\:ss}:{1:00}" -f $new,$frames
}

现在我们可以做:

PS C:\> Add-Frame -Base 00:00:03:14 -Offset 00:00:13:18
00:00:17:02