SQL 分区中的累计总和

Question

考虑与客户进行 table 排序，日期和金额如下

User    Date    Purchase
Joe  '2020-01-01' 10
Joe  '2020-02-01' 20
Joe  '2020-02-20' 20
Joe  '2020-03-15' 15
Lucy '2020-01-12' 5
Lucy '2020-02-15' 30
Lucy '2020-02-21' 20
Lucy '2020-03-05' 30

我想获得一个新列，其中包含之前购买的累计花费，即

User    Date    Purchase Cum
Joe  '2020-01-01' 10      10
Joe  '2020-02-01' 20      30
Joe  '2020-02-20' 20      50
Joe  '2020-03-15' 15      65
Lucy '2020-01-12' 5        5
Lucy '2020-02-15' 30      35
Lucy '2020-02-21' 20      55
Lucy '2020-03-05' 30      85

Answer 1

这将是：

select t.*,
       sum(purchase) over (partition by user order by date) as running_sum
from t;

Answer 2

您可以使用window函数：

sum(purchase) over (partition by user order by date) as purchase_sum

如果window函数不支持那么你可以使用关联子查询:

select t.*,
       (select sum(t1.purchase) 
        from table t1 
        where t1.user = t.user and t1.date <= t.date 
       ) as purchase_sum
from table t;

Answer 3

尝试partition by

    Select  User, Date, Purchase, 
    sum(purchase ) 
    over (partition by User order by user )
     From table

SQL 分区中的累计总和

SQL Cumulative sum in a partition by

sql

partition-by