如何在 Flutter 中将 List<Object> 保存到 SharedPreferences?

How to save List<Object> to SharedPreferences in Flutter?

我有一个最喜欢的音乐列表,我在第一次打开应用程序时从音乐中检索,应用程序从收藏夹中获取最喜欢的音乐列表。我想将此列表保存到共享

preferences.List<Music> favoriteMusic = new List<Music>();

其中音乐 class 是:

class Music {
  final int id;
  final String name, size, rating, duration, img;
  bool favorite;

  Music({
    this.id,
    this.rating,
    this.size,
    this.duration,
    this.name,
    this.img,
    this.favorite,
  });

  factory Music.fromJson(Map<String, dynamic> jsonData){
    return Music(
      id: jsonData['id'],
      rating: jsonData['rating'],
      size: jsonData['size'],
      duration: jsonData['duration'],
      name: jsonData['name'],
      img: jsonData['img'],
      favorite: false,
    );
  }
}

如何保存最喜欢的音乐列表?

您应该执行这些步骤

保存对象:

  1. convert your object to map with toMap() method
  2. encode your map to string with encode(...) method
  3. save the string to shared preferences

用于恢复您的对象:

  1. decode shared preference string to a map with decode(...) method
  2. use fromJson() method to get your object

更新完整样本

import 'dart:convert';

void main() async {
  final SharedPreferences prefs = await SharedPreferences.getInstance();
  
  // Encode and store data in SharedPreferences
  final String encodedData = Music.encode([
    Music(id: 1, ...),
    Music(id: 2, ...),
    Music(id: 3, ...),
  ]);

  await prefs.setString('musics_key', encodedData);

  // Fetch and decode data
  final String musicsString = await prefs.getString('musics_key');

  final List<Music> musics = Music.decode(musicsString);
}

class Music {
  final int id;
  final String name, size, rating, duration, img;
  bool favorite;

  Music({
    this.id,
    this.rating,
    this.size,
    this.duration,
    this.name,
    this.img,
    this.favorite,
  });

  factory Music.fromJson(Map<String, dynamic> jsonData) {
    return Music(
      id: jsonData['id'],
      rating: jsonData['rating'],
      size: jsonData['size'],
      duration: jsonData['duration'],
      name: jsonData['name'],
      img: jsonData['img'],
      favorite: false,
    );
  }

  static Map<String, dynamic> toMap(Music music) => {
        'id': music.id,
        'rating': music.rating,
        'size': music.size,
        'duration': music.duration,
        'name': music.name,
        'img': music.img,
        'favorite': music.favorite,
      };

  static String encode(List<Music> musics) => json.encode(
        musics
            .map<Map<String, dynamic>>((music) => Music.toMap(music))
            .toList(),
      );

  static List<Music> decode(String musics) =>
      (json.decode(musics) as List<dynamic>)
          .map<Music>((item) => Music.fromJson(item))
          .toList();
}

转成字符串,可以存储

import 'dart:convert';
...
var s = json.encode(myList);
// or var s = jsonEncode(myList);

json.decode() //convert a string to List when you load it

对于像我这样想要更多地了解我们亲爱的朋友哈米德在他的回答中所做的魔法,或者想要使他的解决方案适应更复杂的 类 和 lists/other 类,查看这两个链接: https://bezkoder.com/dart-flutter-parse-json-string-array-to-object-list/

https://bezkoder.com/dart-flutter-convert-object-to-json-string/

jsonEncode() 和 jsonDecode() 与 json.encode() 和 json.decode()

相同

Flutter 的 shared_preferences 插件有一个方法:setStringList(String key, List<String> value),所以你可以为你的对象编写序列化程序。

只需在共享首选项中使用字符串列表

basic syntax:

    // read
    final myStringList = prefs.getStringList('my_string_list_key') ?? [];
    // write
    prefs.setStringList('my_string_list_key', ['a', 'b', 'c']);

首先将对象转换为地图。然后使用 jsonEncode 将地图转换为 JSON 字符串,最后将 JSON 字符串保存到共享首选项

Sample example:

        // import 'dart:convert';
    Person person = Person('Mary', 30);
    Map<String, dynamic> map = {
      'name': person.name,
      'age': person.age
    };
    String rawJson = jsonEncode(map);
    prefs.setString('my_string_key', rawJson);

 

检索数据

final rawJson = prefs.getString('my_string_key') ?? '';
Map<String, dynamic> map = jsonDecode(rawJson);
final person = Person(map['name'], map['age']);