JSON 转换为特定格式
JSON conversion to a specific format
我有一个 Java 对象并试图将其转换为特定的 JSON 格式
public class Audit {
String auditId;
String auditData;
}
及以上对象需要转换为以下JSON格式
{
"event":"auditId=100,auditData=purchase order"
}
我们如何使用 Jackson 解析器转换上述格式
您需要为 Audit
class.
编写自定义序列化程序
public class AuditSerializer extends StdSerializer<Audit> {
public AuditSerializer() {
super(Audit.class);
}
protected AuditSerializer(Class<Audit> auditClass) {
super(auditClass);
}
@Override
public void serialize(Audit audit, JsonGenerator gen, SerializerProvider provider) throws IOException {
gen.writeStartObject();
String key = "event";
String value = String.format("auditId=%s,auditData=%s", audit.auditId, audit.auditData);
gen.writeStringField(key, value);
gen.writeEndObject();
}
}
然后使用此自定义序列化程序为 Audit
获取 JSON 字符串:
SimpleModule module = new SimpleModule();
module.addSerializer(new AuditSerializer(Audit.class));
ObjectMapper mapper = new ObjectMapper();
mapper.registerModule(module);
Audit audit = new Audit();
audit.auditId = "100";
audit.auditData = "purchase Order";
System.out.println(mapper.writeValueAsString(audit));
// {"event":"auditId=100,auditData=purchase Order"}
如果用@JsonSerialize(using=AuditSerializer.class)
注解Audit
class,则不需要显式注册AuditSerializer
.
@JsonSerialize(using=AuditSerializer.class)
public class Audit {
...
而你直接使用ObjectMapper
。
Audit audit = new Audit();
audit.auditId = "100";
audit.auditData = "purchase Order";
ObjectMapper mapper = new ObjectMapper();
System.out.println(mapper.writeValueAsString(audit));
// {"event":"auditId=100,auditData=purchase Order"}
我有一个 Java 对象并试图将其转换为特定的 JSON 格式
public class Audit {
String auditId;
String auditData;
}
及以上对象需要转换为以下JSON格式
{
"event":"auditId=100,auditData=purchase order"
}
我们如何使用 Jackson 解析器转换上述格式
您需要为 Audit
class.
public class AuditSerializer extends StdSerializer<Audit> {
public AuditSerializer() {
super(Audit.class);
}
protected AuditSerializer(Class<Audit> auditClass) {
super(auditClass);
}
@Override
public void serialize(Audit audit, JsonGenerator gen, SerializerProvider provider) throws IOException {
gen.writeStartObject();
String key = "event";
String value = String.format("auditId=%s,auditData=%s", audit.auditId, audit.auditData);
gen.writeStringField(key, value);
gen.writeEndObject();
}
}
然后使用此自定义序列化程序为 Audit
获取 JSON 字符串:
SimpleModule module = new SimpleModule();
module.addSerializer(new AuditSerializer(Audit.class));
ObjectMapper mapper = new ObjectMapper();
mapper.registerModule(module);
Audit audit = new Audit();
audit.auditId = "100";
audit.auditData = "purchase Order";
System.out.println(mapper.writeValueAsString(audit));
// {"event":"auditId=100,auditData=purchase Order"}
如果用@JsonSerialize(using=AuditSerializer.class)
注解Audit
class,则不需要显式注册AuditSerializer
.
@JsonSerialize(using=AuditSerializer.class)
public class Audit {
...
而你直接使用ObjectMapper
。
Audit audit = new Audit();
audit.auditId = "100";
audit.auditData = "purchase Order";
ObjectMapper mapper = new ObjectMapper();
System.out.println(mapper.writeValueAsString(audit));
// {"event":"auditId=100,auditData=purchase Order"}