OCR 和提取特定子字符串后的文本 - 使用 Python 的正则表达式

Question

我是 Regex 的新手，所以我确信我遗漏了一些明显的东西，但需要帮助解决以下问题。

我想提取特定子字符串后面的字符串。我正在处理扫描文档列表并具有以下示例字符串，我想在 "FORENAME"

之后提取所有内容

这是我到目前为止所做的：

regex = r"(?<=(FORE))[A-Z]+"

test_str = 'UNIQUE NUMBER 12345 678910 11 FROM THIS DOCUMENT | . ISSUED ON 2011-04-04 FORENAME GUIDO    \ SURNAME VAN ROSSUM.   '

matches = re.finditer(regex, test_str)

for matchNum, match in enumerate(matches, start=1):

    print ("Match {matchNum} was found at {start}-{end}: {match}".format(matchNum = matchNum, start = match.start(), end = match.end(), match = match.group()))

    for groupNum in range(0, len(match.groups())):
        groupNum = groupNum + 1

        print ("Group {groupNum} found at {start}-{end}: {group}".format(groupNum = groupNum, start = match.start(groupNum), end = match.end(groupNum), group = match.group(groupNum)))

return以下是：

 Match 1 was found at 78-82: NAME
 Group 1 found at 74-78: FORE

我想要的 return 是：

GUIDO \ SURNAME VAN ROSSUM.

谢谢！

Answer 1

What I want it to return is:
GUIDO \ SURNAME VAN ROSSUM.

基于以上，您可以使用：

import re
test_str = 'UNIQUE NUMBER 12345 678910 11 FROM THIS DOCUMENT | . ISSUED ON 2011-04-04 FORENAME GUIDO    \ SURNAME VAN ROSSUM.'
result = re.sub(r"^.*FORENAME(.*?)$", r"", test_str)
print(result)
#  GUIDO    \ SURNAME VAN ROSSUM.

Demo

Answer 2

如此简单的问题不需要正则表达式

test_str = 'UNIQUE NUMBER 12345 678910 11 FROM THIS DOCUMENT | . ISSUED ON 2011-04-04 FORENAME GUIDO    \ SURNAME VAN ROSSUM.   '

pos = test_str.find("FORENAME") + len("FORENAME")

print(test_str[pos:])

OCR 和提取特定子字符串后的文本 - 使用 Python 的正则表达式

OCR and extracting text that follows a specific substring - regex using Python

python

regex

ocr

string-matching

text-extraction