通过套接字发送 GET 请求 Python

Question

我正在尝试向使用 Python 3.8.2 的服务器发送 GET 请求。但是，当我执行命令 print(sock.recv(1024)) 时，它只是 returns 给我的指令：

b'\n Iniate communication with GET to retrieve the encrypted messages.\n\n Then return the messages decrypted to the server, taking care to ensure each message is split on to a newline\n '

这是我的代码：

#
# Connect over TCP to the following server 'localhost', 10000
# Initiate communication with GET to retrieve the encrypted messages.
# Then return the messages decrypted to the server,
# taking care to ensure each message is split on to a newline
#


import socket
sock = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
sock.connect(("localhost", 10000))
sock.send(b"GET / HTTP/1.1\r\nHost:127.0.0.1\r\n\r\n")
print(sock.recv(1024))

GET请求有问题吗？

Answer 1

回答我的问题，将行 sock.send(b"GET / HTTP/1.1\r\nHost:127.0.0.1\r\n\r\n") 替换为 sock.send(b"GET") 就成功了。

通过套接字发送 GET 请求 Python

Send GET request over socket Python

get

serversocket

python-3.8