在 PySpark 中写入数据框的自定义文件名

Question

我想写dataframe的记录。记录采用 json 格式。所以我需要用我的自定义文件名而不是 part-0000-cfhbhgh.json.

将内容写入文件

Answer 1

我在 scala 中给出答案，但在 python 中这些也是基本步骤..

 import org.apache.hadoop.fs.{FileSystem, Path}

  val fs: FileSystem = FileSystem.get(spark.sparkContext.hadoopConfiguration);
  val file = fs.globStatus(new Path("data/jsonexample/part*"))(0).getPath().getName()
  println("file name " + file)
  fs.rename(
    new Path("data/jsonexample/" + file)
    , new Path("data/jsonexample/tsuresh97_json_toberenamed.json"))

---

完整示例：

 import spark.implicits._

  val df = Seq(
    (123, "ITA", 1475600500, 18.0),
    (123, "ITA", 1475600500, 18.0),
    (123, "ITA", 1475600516, 19.0)
  ).toDF("Value", "Country", "Timestamp", "Sum")
  df.coalesce(1)
    .write
    .mode(SaveMode.Overwrite)
    .json("data/jsonexample/")

  import org.apache.hadoop.fs.{FileSystem, Path}

  val fs: FileSystem = FileSystem.get(spark.sparkContext.hadoopConfiguration);
  val file = fs.globStatus(new Path("data/jsonexample/part*"))(0).getPath().getName()
  println("file name " + file)
  fs.rename(
    new Path("data/jsonexample/" + file)
    , new Path("data/jsonexample/tsuresh97_json_toberenamed.json"))

结果：

json 内容：

{"Value":123,"Country":"ITA","Timestamp":1475600500,"Sum":18.0}
{"Value":123,"Country":"ITA","Timestamp":1475600500,"Sum":18.0}
{"Value":123,"Country":"ITA","Timestamp":1475600516,"Sum":19.0}