如何检查给定的参数数量并使 python 获取指定文件（如果给定）？

Question

import sys

if __name__ == '__main__':

    print(sys.argv)
    if sys.argv[1]== None:
        print('taking default file 15.wav')

    else:
        print('taking the given specified file:')
        print(sys.argv[1])

它不起作用，如何检查如果给定了文件，程序是否处理了指定的文件？

像这样：

# no file given as arg, so 
# the below will work on default 15.wav file
python program.py

python program.py 4.wav #this will work on 4.wav

Answer 1

像这样尝试：

import sys

if __name__ == '__main__':
    if len (sys.argv) > 1 :
        print('taking the given specified file:', sys.argv [1])
    else :
        print('taking default file 15.wav')

如何检查给定的参数数量并使 python 获取指定文件（如果给定）？

how to check how many args given and make python take specified file if it's given?

python

args

sys