在 rest API 中应用 @OrderBy 注释而不是排序
Apply @OrderBy annotation in rest API not ordering
我正在尝试在我的 Rest API 中应用 @OrderBy
注释,我正在尝试按 styleName
对输出进行排序,但是,它不是按styleName
并且仍然按 ID 顺序显示所有这些。我正在邮递员中对此进行测试。我如何实施 @OrderBy
注释错误。
我为 @OrderBy
使用的导入语句是
import javax.persistence.OrderBy;
我知道我可以像这样创建一个新查询
@NamedQuery(name = "Styles.findAll", query = "SELECT s FROM Styles s ORDER BY s.name")
但是,我想使用 @OrderBy
注释
我把@Orderby
注解放在Controller方法里面,控制器是
@GetMapping(produces=MediaType.APPLICATION_JSON_VALUE)
@OrderBy("Styles.styleName DESC")
public List<Styles> GetAllStyles() {
return service.getAllStyles();
}
是否可以做一些类似于服务和控制器的事情,而不是过滤数据,它可以按列的名称排序
服务是
public List<Styles> getAllStyles() {
EntityManager em = DBUtil.getEMF().createEntityManager();
List<Styles> list = null;
try {
list = em.createNamedQuery("Styles.findAll", Styles.class)
.getResultList();
if (list == null || list.isEmpty()) {
list = null;
}
} finally {
em.close();
}
return list;
}
我使用的 JPA 是
@Entity
@Table(name = "styles")
@NamedQueries({
@NamedQuery(name = "Styles.findAll", query = "SELECT s FROM Styles s"),
@NamedQuery(name = "Styles.findById", query = "SELECT s FROM Styles s WHERE s.id = :id"),
@NamedQuery(name = "Styles.findByCatId", query = "SELECT s FROM Styles s WHERE s.catId = :catId"),
@NamedQuery(name = "Styles.findByStyleName", query = "SELECT s FROM Styles s WHERE s.styleName = :styleName"),
@NamedQuery(name = "Styles.findByLastMod", query = "SELECT s FROM Styles s WHERE s.lastMod = :lastMod")})
public class Styles implements Serializable {
private static final long serialVersionUID = 1L;
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Basic(optional = false)
@Column(name = "id")
private Integer id;
@Basic(optional = false)
@NotNull
@Column(name = "cat_id")
private int catId;
@Basic(optional = false)
@NotNull
@Size(min = 1, max = 255)
@Column(name = "style_name")
private String styleName;
@Basic(optional = false)
@NotNull
@Column(name = "last_mod")
@Temporal(TemporalType.TIMESTAMP)
private Date lastMod;
public Styles() {
}
public Styles(Integer id) {
this.id = id;
}
public Styles(Integer id, int catId, String styleName, Date lastMod) {
this.id = id;
this.catId = catId;
this.styleName = styleName;
this.lastMod = lastMod;
}
public Integer getId() {
return id;
}
public void setId(Integer id) {
this.id = id;
}
public int getCatId() {
return catId;
}
public void setCatId(int catId) {
this.catId = catId;
}
public String getStyleName() {
return styleName;
}
public void setStyleName(String styleName) {
this.styleName = styleName;
}
public Date getLastMod() {
return lastMod;
}
public void setLastMod(Date lastMod) {
this.lastMod = lastMod;
}
@Override
public int hashCode() {
int hash = 0;
hash += (id != null ? id.hashCode() : 0);
return hash;
}
@Override
public boolean equals(Object object) {
// TODO: Warning - this method won't work in the case the id fields are not set
if (!(object instanceof Styles)) {
return false;
}
Styles other = (Styles) object;
if ((this.id == null && other.id != null) || (this.id != null && !this.id.equals(other.id))) {
return false;
}
return true;
}
@Override
public String toString() {
return "Service.Styles[ id=" + id + " ]";
}
由于您正在使用 javax.persistence.OrderBy,并遵循其文档,因此应将其应用于 Entity 或 JPA(具体针对 Spring)以使其正常工作
我正在尝试在我的 Rest API 中应用 @OrderBy
注释,我正在尝试按 styleName
对输出进行排序,但是,它不是按styleName
并且仍然按 ID 顺序显示所有这些。我正在邮递员中对此进行测试。我如何实施 @OrderBy
注释错误。
我为 @OrderBy
使用的导入语句是
import javax.persistence.OrderBy;
我知道我可以像这样创建一个新查询
@NamedQuery(name = "Styles.findAll", query = "SELECT s FROM Styles s ORDER BY s.name")
但是,我想使用 @OrderBy
注释
我把@Orderby
注解放在Controller方法里面,控制器是
@GetMapping(produces=MediaType.APPLICATION_JSON_VALUE)
@OrderBy("Styles.styleName DESC")
public List<Styles> GetAllStyles() {
return service.getAllStyles();
}
是否可以做一些类似于服务和控制器的事情,而不是过滤数据,它可以按列的名称排序
服务是
public List<Styles> getAllStyles() {
EntityManager em = DBUtil.getEMF().createEntityManager();
List<Styles> list = null;
try {
list = em.createNamedQuery("Styles.findAll", Styles.class)
.getResultList();
if (list == null || list.isEmpty()) {
list = null;
}
} finally {
em.close();
}
return list;
}
我使用的 JPA 是
@Entity
@Table(name = "styles")
@NamedQueries({
@NamedQuery(name = "Styles.findAll", query = "SELECT s FROM Styles s"),
@NamedQuery(name = "Styles.findById", query = "SELECT s FROM Styles s WHERE s.id = :id"),
@NamedQuery(name = "Styles.findByCatId", query = "SELECT s FROM Styles s WHERE s.catId = :catId"),
@NamedQuery(name = "Styles.findByStyleName", query = "SELECT s FROM Styles s WHERE s.styleName = :styleName"),
@NamedQuery(name = "Styles.findByLastMod", query = "SELECT s FROM Styles s WHERE s.lastMod = :lastMod")})
public class Styles implements Serializable {
private static final long serialVersionUID = 1L;
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Basic(optional = false)
@Column(name = "id")
private Integer id;
@Basic(optional = false)
@NotNull
@Column(name = "cat_id")
private int catId;
@Basic(optional = false)
@NotNull
@Size(min = 1, max = 255)
@Column(name = "style_name")
private String styleName;
@Basic(optional = false)
@NotNull
@Column(name = "last_mod")
@Temporal(TemporalType.TIMESTAMP)
private Date lastMod;
public Styles() {
}
public Styles(Integer id) {
this.id = id;
}
public Styles(Integer id, int catId, String styleName, Date lastMod) {
this.id = id;
this.catId = catId;
this.styleName = styleName;
this.lastMod = lastMod;
}
public Integer getId() {
return id;
}
public void setId(Integer id) {
this.id = id;
}
public int getCatId() {
return catId;
}
public void setCatId(int catId) {
this.catId = catId;
}
public String getStyleName() {
return styleName;
}
public void setStyleName(String styleName) {
this.styleName = styleName;
}
public Date getLastMod() {
return lastMod;
}
public void setLastMod(Date lastMod) {
this.lastMod = lastMod;
}
@Override
public int hashCode() {
int hash = 0;
hash += (id != null ? id.hashCode() : 0);
return hash;
}
@Override
public boolean equals(Object object) {
// TODO: Warning - this method won't work in the case the id fields are not set
if (!(object instanceof Styles)) {
return false;
}
Styles other = (Styles) object;
if ((this.id == null && other.id != null) || (this.id != null && !this.id.equals(other.id))) {
return false;
}
return true;
}
@Override
public String toString() {
return "Service.Styles[ id=" + id + " ]";
}
由于您正在使用 javax.persistence.OrderBy,并遵循其文档,因此应将其应用于 Entity 或 JPA(具体针对 Spring)以使其正常工作