如何估计迭代时间并用 for 循环的 tqdm 显示它?

How to estimate the iteration time and display it with tqdm of a for loop?

我想估计以下代码迭代的持续时间并将其显示在进度条 (tdqm) 上。此函数将给出 string.printable.

的所有可能组合
import strings
from itertools import combinations

def generate_combinations(iterable):
  lst = list(iterable)
  for lenght in range(0, len(lst) + 1):
    for i in combinations(lst, lenght):
      with open('passwords.txt', 'a') as f:
        w = ''.join(map(str, i))
        f.write(w + '\n')

generate_combinations(string.printable)

我想你可以使用 timetqdm 来做到这一点。

预期输出:

estimated time: 12 seconds left
tqdm progress bar: 12% |||||||...

最终答案(根据@jq170727的建议)如下代码:


import string
from tqdm.auto import trange, tqdm
from itertools import permutations

请求的生成器(在 google colab 上,使用 TPU:大约 10k it / s)

def combined(lst, lenStart, lenEnd):
  for i in trange(lenStart, lenEnd + 1, desc='Progress'):
    for subset in tqdm(permutations(lst, i),  desc='Subsets', leave = False):
      w = ''.join(map(str, subset))
      yield w

在这里我们得到了效率更高的相同生成器(在 google colab 上,使用 TPU:大约 950k / s)

def compress_permutation(lst, lenStart, lenEnd):
  yield ','.join([''.join(map(str, subset)) for i in trange(lenStart, lenEnd + 1, desc='Progress') for subset in tqdm(permutations(lst, i), desc='Subsets', leave = False)])
iterable = list(string.printable[:94])
lenStart, lendEnd = 1, 9

for subset in compress_permutation(iterable, l1, l2):
  with open('passwords.txt', 'a') as f:
    f.write(subset)