SQL 计算 DATEDIFF 的平均值的查询

Question

我正在尝试编写一个查询，为我提供 AVG 的 Datediff

我有一个类似的查询，我正在尝试用我的新查询复制它，它是：

SELECT DATENAME(MONTH, d.OPENED) AS MonthValue, 
SUM(CASE WHEN d.ASSGNTO = 'E099255' AND d.REV_CLS = 2 THEN 
1 ELSE 0 END) AS SmallCommercialIndust, 
SUM(CASE WHEN d.ASSGNTO = 'E099255' AND d.REV_CLS <> 2 THEN 1 
ELSE 0 END) AS Residential
FROM hb_Disputes d
WHERE YEAR(d.OPENED) = YEAR(GETDATE())
GROUP BY DATENAME(MONTH, d.OPENED) 
ORDER BY MIN(d.OPENED);

这是我的输出：

Month Value  Small Commercial Indust     Residential
----------------------------------------------------
January             0                         0
February            0                         0
March               1                         0
April               0                         2
May                 0                         1
June                0                         1
July                1                         0
August              1                         0
September           0                         1
October             1                         0
November            1                         0
December            0                         1

下面是我正在尝试创建的 Query，它采用相同的信息，但在需要 d.OPENS 的地方添加了一个额外的组件，并将其减去 d.DATERLVD 并为我提供本月 AVG：

SELECT DATENAME(MONTH, d.OPENED) AS MonthValue, 
SUM(CASE WHEN d.ASSGNTO = 'E099255' AND d.REV_CLS = 2 THEN 1 
ELSE 0 END AND AVG(DATEDIFF(day, d.OPENED, d.DATERLVD)) AS 
SmallCommercialIndust, 
SUM(CASE WHEN d.ASSGNTO = 'E099255' AND d.REV_CLS <> 2  THEN 1 
ELSE 0 END AND AVG(DATEDIFF(day, d.OPENED, d.DATERLVD)) AS 
Residential
FROM hb_Disputes d
WHERE YEAR(d.OPENED) = YEAR(GETDATE())
GROUP BY DATENAME(MONTH, d.OPENED)
ORDER BY MIN(d.OPENED);

Answer 1

为什么要在 SELECT 子句中使用 AND？我想你想要：

SELECT DATENAME(MONTH, d.OPENED) AS MonthValue, 
       SUM(CASE WHEN d.ASSGNTO = 'E099255' AND d.REV_CLS = 2 THEN 1 ELSE 0 END) as SmallCommercialIndust,
       AVG(CASE WHEN d.ASSGNTO = 'E099255' AND d.REV_CLS = 2 THEN DATEDIFF(day, d.OPENED, d.DATERLVD) END) AS SmallCommercialIndust_avg, 
       SUM(CASE WHEN d.ASSGNTO = 'E099255' AND d.REV_CLS <> 2 THEN 1 ELSE 0 END) as Residential,
       AVG(CASE WHEN d.ASSGNTO = 'E099255' AND d.REV_CLS <> 2 THEN DATEDIFF(day, d.OPENED, d.DATERLVD) END) AS Residential_avg
FROM hb_Disputes d

Answer 2

了解如何正确设置代码格式。你可以清楚地看到你把括号放错了。

SELECT DATENAME(MONTH, d.OPENED) AS MonthValue
    , SUM(
        CASE 
            WHEN d.ASSGNTO = 'E099255' AND d.REV_CLS = 2 THEN 1 
            ELSE 0 
        END 
        AND 
            AVG(DATEDIFF(day, d.OPENED, d.DATERLVD)
    ) AS SmallCommercialIndust
    , SUM(
        CASE 
            WHEN d.ASSGNTO = 'E099255' AND d.REV_CLS <> 2  THEN 1 
            ELSE 0 
        END
        AND AVG(DATEDIFF(day, d.OPENED, d.DATERLVD)
    ) AS Residential
FROM hb_Disputes d
WHERE YEAR(d.OPENED) = YEAR(GETDATE())
GROUP BY DATENAME(MONTH, d.OPENED)
ORDER BY MIN(d.OPENED);

SQL 计算 DATEDIFF 的平均值的查询

SQL Query to calculate the AVG of DATEDIFF

sql

sql-server

datediff