根据 SQL SERVER 2000 中的条件计算行数

Question

我想从 SQL SERVER 2000

中获取以下格式的数据

Department | TotalPresent | Employee | Officer
XYZ              12           6          6

我正在运行查询

SELECT     a.department,
           Count(emp_id) AS totalpresent,
           CASE
                      WHEN a.type = 'Employee' THEN Count(a.type)
                      ELSE 0
           END AS employee,
           CASE
                      WHEN a.type = 'Officer' THEN Count(a.type)
                      ELSE 0
           END AS officer
FROM       attendancelog m
INNER JOIN employeedata a
ON         m.emp_id = a.emp_id groupby a.type,
           a.department

当我运行这个查询时，我得到了这种不正确的数据

Department | TotalPresent | Employee | Officer
    XYZ              12           6         0
    XYZ              12           0         6

请纠正我似乎是什么问题为什么它返回我两次相同的记录但满足条件

我只想根据类型是员工还是官员来计算行数

Answer 1

从 group by 中删除 type 并将 case 移到 sum() 中：

Select a.department, count(emp_id) as TotalPresent,
       sum(case when a.Type = 'Employee' THEN 1 ELSE 0 END) as Employee,
       sum(case when a.Type = 'Officer' THEN 1 ELSE 0 END) as Officer
from AttendanceLog m INNER JOIN
     EmployeeData a
     ON m.emp_id = a.emp_id
GroupBy a.Department;

另外，升级您的 SQL 服务器。 SQL Server 2000 多年来一直不受支持。您应该尝试使用支持的软件。

根据 SQL SERVER 2000 中的条件计算行数

Count Rows On a Condition in SQL SERVER 2000

sql

sql-server-2000