登录方法“_mulFromInteger”被调用为空
sign in The method '_mulFromInteger' was called on null
我已经在我的供应商中获得了登录方法。
Future<void> signIn(
String email, String password, BuildContext context) async {
SharedPreferences sharedPreferences = await SharedPreferences.getInstance();
final clientID = "com.super.app";
final body = "username=$email&password=$password&grant_type=password";
final String clientCredentials =
const Base64Encoder().convert("$clientID:".codeUnits);
try {
final http.Response response =
await http.post("http://localhost:8888/auth",
headers: {
"Content-Type": "application/x-www-form-urlencoded",
"Authorization": "Basic $clientCredentials"
},
body: body);
final jsonResponse = json.decode(response.body);
// if (jsonResponse["error"] != null) {
// throw HttpException(jsonResponse["error"]);
// }
_userId = 1;
_token = jsonResponse['access_token'];
_expiryDate = DateTime.now().add(
Duration(
seconds: jsonResponse['expires_in'],
),
);
_autoLogout();
notifyListeners();
final userData = json.encode(
{
'userId': 1,
'email': email,
'token': _token,
'expiryDate': _expiryDate.toIso8601String(),
},
);
sharedPreferences.setString('userData', userData);
} catch (error) {
print(error.toString()); //<-- misleading error
}
}
一切正常,但当传递的登录凭据不正确时,我会收到误导性错误
flutter: NoSuchMethodError: The method '_mulFromInteger' was called on null.
Receiver: null
Tried calling: _mulFromInteger(1000000)
后端传递错误代码 400 和正文 {"error": "invalid client"} 但我得到那个奇怪的错误作为输出。那么这个错误是什么意思,为什么我得到那个而不是 body
根据@Suragch 的评论,我的代码几乎没有问题。首先我认为当服务器 return 400 代码然后它会自动抛出错误并跳过其余行..我错了所以基本上我不得不取消注释我的代码以获取 http 异常并在我的按钮中捕获错误
try {
await Provider.of<Auth>(context, listen: false).signIn(
emailController.text, passwordController.text);
} on HttpException catch (error) {
print(error.toString());
} catch (error) {
print(error);
}
我已经在我的供应商中获得了登录方法。
Future<void> signIn(
String email, String password, BuildContext context) async {
SharedPreferences sharedPreferences = await SharedPreferences.getInstance();
final clientID = "com.super.app";
final body = "username=$email&password=$password&grant_type=password";
final String clientCredentials =
const Base64Encoder().convert("$clientID:".codeUnits);
try {
final http.Response response =
await http.post("http://localhost:8888/auth",
headers: {
"Content-Type": "application/x-www-form-urlencoded",
"Authorization": "Basic $clientCredentials"
},
body: body);
final jsonResponse = json.decode(response.body);
// if (jsonResponse["error"] != null) {
// throw HttpException(jsonResponse["error"]);
// }
_userId = 1;
_token = jsonResponse['access_token'];
_expiryDate = DateTime.now().add(
Duration(
seconds: jsonResponse['expires_in'],
),
);
_autoLogout();
notifyListeners();
final userData = json.encode(
{
'userId': 1,
'email': email,
'token': _token,
'expiryDate': _expiryDate.toIso8601String(),
},
);
sharedPreferences.setString('userData', userData);
} catch (error) {
print(error.toString()); //<-- misleading error
}
}
一切正常,但当传递的登录凭据不正确时,我会收到误导性错误
flutter: NoSuchMethodError: The method '_mulFromInteger' was called on null.
Receiver: null
Tried calling: _mulFromInteger(1000000)
后端传递错误代码 400 和正文 {"error": "invalid client"} 但我得到那个奇怪的错误作为输出。那么这个错误是什么意思,为什么我得到那个而不是 body
根据@Suragch 的评论,我的代码几乎没有问题。首先我认为当服务器 return 400 代码然后它会自动抛出错误并跳过其余行..我错了所以基本上我不得不取消注释我的代码以获取 http 异常并在我的按钮中捕获错误
try {
await Provider.of<Auth>(context, listen: false).signIn(
emailController.text, passwordController.text);
} on HttpException catch (error) {
print(error.toString());
} catch (error) {
print(error);
}