Python regex 如何使用 NOT 条件检查组反向引用或忽略反向引用中的组项

Question

问题：- 如果备用号码不同，则号码有效。如果备用号码相同且中间号码也相同，则它们再次有效

example:-
123456 :- This number is valid as we don't have any alternate number as same, all are different
110100:- This number is invalid as in  010  alternate numbers are same and in-between is different
110000 :- this number is valid as in 000 alternate number though are same in-between is also same

我试过的

import re
st="1101010"
#st="110000"
re.findall(r"(\d)[^]&[\d]", st)

我试图通过反向引用和使用 AND 条件来取消组项目，但这不起作用。

Answer 1

您可以使用正则表达式

r"(\d)(?!)\d"

匹配此正则表达式的字符串包含字符串 aba，其中 a 是任何字符，b 是 a 以外的任何字符。

Regex demo

Python demo

Python 的正则表达式引擎执行以下操作。

(\d)    # match a digit and save to cap grp 1
(?!)  # the next char cannot be the content of cap grp 1
\d      # match a digit
      # match the content of cap grp 1

Python regex 如何使用 NOT 条件检查组反向引用或忽略反向引用中的组项

Python regex How to check with NOT condition for group backreference OR ignoring a group item in backreference

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