C - Switch-case 打印 case 两次

Question

我写了下面的 switch-case:

    char input;
    int run = 1;
    while(run){
        printf("Would you like to update the student's name? Enter Y or N (Y=yes, N=no)\n");
        input = getchar();
        switch (input)
        {
        case 'N':
            run = 0;
            break;
        case 'n':
            run = 0;
            break;
        case 'Y':
            printf("Please enter the updated name\n");
            scanf("%s", st->name);
            run = 0;
            break;
        case 'y':
            printf("Please enter the updated name\n");
            scanf("%s", st->name);
            run = 0;
            break;
        case '\n':
            break;
        default:
            printf("Wrong input. Please enter a valid input (Y or N)\n");
        }
    }

当我运行它这样做时：

Please enter the id of the student that you would like to update
1
Would you like to update the student's name? Enter Y or N (Y=yes, N=no)
Would you like to update the student's name? Enter Y or N (Y=yes, N=no)

为什么它会打印两次问题？谁能帮忙？除此之外，情况运行符合预期。

Answer 1

函数getchar读取所有字符，包括换行符。而是使用

scanf( " %c", &input );

您的 switch 语句也有重复的代码。例如写

    switch (input)
    {
    case 'N':
    case 'n':
        run = 0;
        break;
    case 'Y':
    case 'y':
        printf("Please enter the updated name\n");
        scanf("%s", st->name);
        run = 0;
        break;
   //...

您可以对 switch 语句的其他标签使用相同的方法。并删除此代码

    case '\n':
        break;

C - Switch-case 打印 case 两次

C - Switch-case prints case twice

c

scanf

switch-statement

getchar