如何仅对具有 Spring RestController 的对象的子对象应用 @JsonView - 序列化？

Question

我有这个案例：

public class Project{

    private long id;

    private List<User> users;

    // other properties and getter setter etc
}

public class User{

   @JsonView(MinimalUser.class) 
   private long id;

   @JsonView(MinimalUser.class)
   private String name;

   private ComplexObject anything;

}

现在的 RestMethod：


    @JsonView(MinimalUser.class)
    @GetMapping("/client/{id}")
    public List<Project> findProjectsByClientId(@PathVariable long id) {
        return projectService.findProjectsByClientId(id);
    }

这里我只想要一个用最少的 Users 对象初始化的项目，但是什么都不会初始化，因为我的项目中没有 "MinimalUser.class" JsonView，因此它没有被初始化。

我不想将 @JsonView 批注放在项目中的所有变量中，因为这太过分了。

如何告诉控制器只将@JsonView-Filtering/Serialization 应用到项目的用户（子）？

因为这个调用工作正常（我只得到必填字段）：


    @JsonView(MinimalUser.class)
    @GetMapping("/minimal")
    public List<User> findAllUsers() {
        return userService.findAllUsers();
    }

Answer 1

如果扩展 MinimalUser 视图并将这个新视图应用于整个项目，您可以获得以下结果：

public class MinimalProject extends MinimalUser {}
public class DetailedProject extends MinimalProject {}

// apply view to entire class
@JsonView(MinimalProject.class)
public class Project {
    // keep existing fields as is

    // limit view for project
    @JsonView(DetailedProject.class)
    private String details;
}

// test
ObjectMapper mapper = new ObjectMapper().disable(MapperFeature.DEFAULT_VIEW_INCLUSION);

User u = new User();
u.setId(1);
u.setName("John Doe");
u.setEmail("john@doe.com");
u.setDetails("some details");

System.out.println("user default view: " + mapper.writeValueAsString(u));

System.out.println("user minimal view: " + mapper.writerWithView(MinimalUser.class).writeValueAsString(u));

Project p = new Project();

p.setId(1000);
p.setName("MegaProject");
p.setUsers(Arrays.asList(u));
p.setDetails("Project details: worth M");

System.out.println("project default view: " + mapper.writeValueAsString(p));

System.out.println("project minimal view: " + mapper.writerWithView(MinimalProject.class).writeValueAsString(p));

输出:

user default view: {"id":1,"name":"John Doe","details":"some details","email":"john@doe.com"}
user minimal view: {"id":1,"name":"John Doe"}
project default view: {"id":1000,"users":[{"id":1,"name":"John Doe","details":"some details","email":"john@doe.com"}],"name":"MegaProject","details":"Project details: worth M"}
project minimal view: {"id":1000,"users":[{"id":1,"name":"John Doe"}],"name":"MegaProject"}

如何仅对具有 Spring RestController 的对象的子对象应用 @JsonView - 序列化？

How to Apply @JsonView only for children of a Object with Spring RestController - serialization?

java

serialization

spring

jackson

json-view