伙计们请帮我纠正“111”和“222”因为我纠正了“333”及以上系列

Question

伙计们，我对回文有一个疑问。我为数字回文写了一个程序。它执行成功，但是当我输入 333 时我得到了正确的输出，当我输入 111 时我得到了错误的输出。我不知道出了什么问题，因为当我执行上面的 3 时会给出正确的输出，但是当我执行下面的 3 时我得到了错误的输出。请帮我解决我做错了什么。

public class Practice1 {
    public static void main(String[] args) {
        int num = 121, res = 0, var = 0, c = num;
        for (int i = 1; i <= num; i++) {
            res = num % 10;
            var = var * 10 + res;
            num = (num) / 10;
        }
        if (var == c) {
            System.out.println(c + " is a Palindrome Number");
        } else {
            System.out.println(c + " is not a Palindrome Number");
        }
    } 
}

Answer 1

你可以使用while循环

    public static void main(String[] args) {
        int num = 121, res = 0, var = 0, c = num;
        while (num != 0) {
            res = num % 10;
            var = var * 10 + res;
            num = (num) / 10;
        }
        if (var == c) {
            System.out.println(c + " is a Palindrome Number");
        } else {
            System.out.println(c + " is not a Palindrome Number");
        }
    }

伙计们请帮我纠正“111”和“222”因为我纠正了“333”及以上系列

Guys Plz help me to get correct out for "111" and "222" Because I got correct for "333" and above series

java

palindrome