仅忽略 AssertJ 中的嵌入式成员

Question

我有两个 class 要用 JUnit/Mockito 测试：

 public class ClassA {

    private int sk;
    // getters and setters

} 


 public class ClassB {

    private int sk;
    private List<ClassA> lista;

    // getters and setters

}

然后在我的测试中 class，使用 AssertJ:

   List<ClassA> lista = //... populated with list of objects of ClassA

   ClassB expected = new ClassB();
   expected.setSk(5);
   expected.setLista(lista);

   ClassB actual = getItFromTheClassToTest();   

   assertThat(actual).usingRecursiveComparison()
                    .ignoringFields("sk")  // need to ignore only classA.sk
                    .isEqualTo(expected);

问题是名称 sk 在两个 class 中都有，我只需要在 ClassA 中忽略它，而不是在 ClassB 中。这在 AssertJ 中可能吗？

Answer 1

根据 ignoringFields javadoc:

Nested fields can be specified like this: home.address.street.

...因此您的类:

ClassB b = new ClassB(1, Arrays.asList(new ClassA(1)));
ClassB bIsEqualsExceptForNestedField = new ClassB(1, Arrays.asList(new ClassA(2)));
ClassB bIsNotEquals = new ClassB(2, Arrays.asList(new ClassA(3)));

// should succeed
assertThat(b)
    .usingRecursiveComparison()
    .ignoringFields("lista.sk")
    .isEqualTo(bIsEqualsExceptForNestedField);
// should fail
assertThat(b)
    .usingRecursiveComparison()
    .ignoringFields("lista.sk")
    .isEqualTo(bIsNotEquals);

仅忽略 AssertJ 中的嵌入式成员

Ignoring only embedded member in AssertJ

java

junit

mockito

assertj