Kivy、StackLayout、对象顺序

Kivy, StackLayout, object order

我有一个带有 StackLayout 的屏幕。堆栈的第一行包括一个文本输入和一个“+”按钮,这意味着在循环中的实际行下方添加另一个相同的行(即另一个带有另一个 "add" 按钮的文本输入)。然后有一个 "Save" 按钮,它应该总是在堆栈的末尾。 字典应该稍后在按下保存按钮时从文本字段中获取输入,但这应该与我的问题无关。

我的代码有两个问题:

我知道 kivy 为小部件分配了相反的顺序(即最后添加的将首先绘制),这就是我手动为新行分配索引的原因。但是,我无法实现所需的行为。

这是一个最小的工作版本:

from kivy.app import App
from kivy.uix.button import Button
from kivy.uix.textinput import TextInput
from kivy.uix.stacklayout import StackLayout
from kivy.uix.screenmanager import ScreenManager, Screen

class AddWindow(Screen):
    def __init__(self, **kwargs):
        super(AddWindow, self).__init__(**kwargs)

        self.grid = StackLayout()
        self.grid.pos_hint = {"x":0.05,"top":0.8}
        self.grid.size_hint = (0.9,None)
        self.add_widget(self.grid)

        self.i = 1
        self.n = 1
        self.inputs = {}
        self.ing1 = TextInput(size_hint=(0.9,'0.3sp'))
        self.grid.add_widget(self.ing1)
        self.inputs['0'] = 'ing1'

        self.addIng = Button(text="+", size_hint=(0.1,'0.3sp'))
        self.addIng.bind(on_press=self.addIngredient)
        self.grid.add_widget(self.addIng)

        self.doneButton = Button(text="Save")
        self.grid.add_widget(self.doneButton, index=0)

    def addIngredient (self, instance):
        self.ing = TextInput(size_hint=(0.9,'0.3sp'))
        self.inputs[self.i] = 'ing{}'.format(self.i+1)
        self.grid.add_widget(self.ing, index=self.n+1)

        self.addNext = Button(text="+", size_hint=(0.1,'0.3sp'))
        self.addNext.bind(on_press=self.addIngredient)
        self.grid.add_widget(self.addNext, index=self.n+2)
        self.i += 1
        self.n += 2
        print(self.inputs)        

WMan = ScreenManager() 
WMan.add_widget(AddWindow(name='add'))


class RecipApp(App):
    def build(self):
        return WMan

if __name__ == "__main__":
    RecipApp().run()

我错过了什么?为了更清楚起见,这是一个屏幕截图: Screenshot

这是一种蛮力方法,通过在每次按下 + `按钮时重建 StackLayout 来执行您想要的操作:

def addIngredient(self, instance):
    tmp_children_list = self.grid.children[:]
    self.grid.clear_widgets()
    for index in range(len(tmp_children_list)-1, -1, -1):
        child = tmp_children_list[index]
        self.grid.add_widget(child)
        if child == instance:
            # this is the pressed Button, so add new row after it
            self.n += 1
            self.ing = TextInput(size_hint=(0.9,'0.3sp'))
            self.ing.text = str(self.n)  # add text just for identification
            self.grid.add_widget(self.ing)
            self.addNext = Button(text="+", size_hint=(0.1,'0.3sp'))
            self.addNext.bind(on_press=self.addIngredient)
            self.grid.add_widget(self.addNext)

这是一种快速而肮脏的方法,由于删除并添加了保存按钮,您的问题应该得到解决。在你最终再次添加保存按钮之前,你在这些操作之间添加了一个新行。希望它能帮助你调整你的代码。关键部分是AddButton的自定义on_press方法。

from kivy.app import App
from kivy.uix.stacklayout import StackLayout
from kivy.uix.textinput import TextInput
from kivy.uix.button import Button
from kivy.core.window import Window


class AddButton(Button):
    def __init__(self, **kwargs):
        super(AddButton, self).__init__(**kwargs)

    def on_press(self):
        self.parent.remove_widget(self.parent.save_btn)
        self.parent.add_widget(TextInput(size_hint=(None, None), size=(Window.width * 0.8 - self.parent.padding[1], Window.height * 0.1)))
        self.parent.add_widget(AddButton(text="+", size_hint=(None, None), size=(Window.width * 0.2, Window.height * 0.1)))
        self.parent.add_widget(self.parent.save_btn)


class MyApp(App):
    def build(self):
        Window.size = (400, 600)
        layout = StackLayout(orientation="lr-tb", padding=(20, 40))
        layout.save_btn = Button(text="Save", size_hint=(None, None),
                               size=(Window.width - layout.padding[1], Window.height * 0.1))

        layout.add_widget(TextInput(size_hint=(None, None), size=(Window.width * 0.8 - layout.padding[1], Window.height * 0.1)))
        layout.add_widget(AddButton(text="+", size_hint=(None, None), size=(Window.width * 0.2, Window.height * 0.1)))

        layout.add_widget(layout.save_btn)

        return layout

MyApp().run()