从文件名中删除双前缀

Question

我的文件嵌套在文件夹中。如果文件名以重复两次的字符串开头，我想将文件名更改为使该字符串只出现一次的名称。

例如：

重命名"Dirty Projectors - Dirty Projectors - Search For Life.mp3" 至 "Dirty Projectors - Search For Life.mp3"
将 "Eefje de Visser - Eefje de Visser - Bitterzoet.mp3" 重命名为 "Eefje de Visser - Bitterzoet.mp3"
保持 "Feng Suave - Maybe Another Time.mp3" 不变。

如何在 Linux 中使用命令行执行此操作？

Answer 1

How can I do this using command-line in Linux?

经过一些研究，它似乎有点复杂。因此，它可能最终会出现在脚本中。

renameMusic.sh

#!/bin/bash

DIRECTORY=
cd ${DIRECTORY}
echo "Normalize filenames in $(pwd)"

for FILENAME in *; do
  echo
  echo "Checking file ${FILENAME}"

  # Count number of dash (-)
  NUMBER=$(grep -o '-' <<< ${FILENAME} | wc -l)
  echo "Found ${NUMBER} of dash (-)"

  # Check if the artist name seems to be there twice
  if [[ "${NUMBER}" -eq 2 ]]; then
    # If so, remove the double part
    NEWFILENAME=$(echo "${FILENAME}" | cut -d "-" -f 2- | sed -e 's/^[[:space:]]*//')
    echo "Going to move to new name ${NEWFILENAME}"

    # mv ${FILENAME} ${NEWFILENAME}

  fi

done

感谢

Looping through ls results in Bash shell script
How to loop through file names returned by find?
Count total number of occurrences using grep
Comparing numbers in Bash
How to trim whitespace from a Bash variable?
Whats the difference between rename and mv
When to wrap quotes around a shell variable?

Answer 2

我结合了@Barmar 的正则表达式和@U880D 的shell 脚本以递归地删除文件名中的任何重复前缀。使用 find 和 perl-rename 时出现问题，所以我不得不这样做：

#!/bin/bash
shopt -s globstar;
for DIR in ${PWD}/**/; do
    cd "${DIR}"
    for FILENAME in *.mp3 ; do
        NEWFILENAME=$(echo "${FILENAME}" | perl -pe 's/^(.*)//')
        if [ "${FILENAME}" != "${NEWFILENAME}" ] ; then
            mv "${FILENAME}" "${NEWFILENAME}"
        fi
    done
done

从文件名中删除双前缀

Remove double prefix from filenames

bash

rename

move

duplicates