按下后如何删除回车 return 字符?
How to remove carriage return char after it's pressed?
我有一个仅限于输入数字的文本区域。我想在用户按下回车键后删除回车 return 字符。这是我的代码:
// Change tempo
function changeTempo(event:KeyboardEvent):void {
if (event.charCode == 13) {
// Some code here
}
// Remove enter char
removeCarriageReturnsAndNewLines(tempo_txt.text);
}
function removeCarriageReturnsAndNewLines($myString:String):String {
var newString:String;
var findCarriageReturnRegExp:RegExp = new RegExp("\r", "gi");
newString = $myString.replace(findCarriageReturnRegExp, "");
var findNewLineRegExp:RegExp = new RegExp("\n", "gi");
newString = newString.replace(findNewLineRegExp, "");
return newString;
}
我想说最简单的方法是听文本输入,像这样:
var t:TextArea = this.ta; //ta is on the timeline
t.restrict = "0-9"; //restricts the input only to numbers
t.addEventListener(TextEvent.TEXT_INPUT, onTextInput, true); //use capture phase to be able to prevent the default behavior (text input)
function onTextInput(e:TextEvent):void {
if(e.text.indexOf("\n") > -1) {
e.preventDefault(); //prevent the default behavior of the field
}
}
我现在无法对此进行测试,但我想它应该可以正常工作。
我有一个仅限于输入数字的文本区域。我想在用户按下回车键后删除回车 return 字符。这是我的代码:
// Change tempo
function changeTempo(event:KeyboardEvent):void {
if (event.charCode == 13) {
// Some code here
}
// Remove enter char
removeCarriageReturnsAndNewLines(tempo_txt.text);
}
function removeCarriageReturnsAndNewLines($myString:String):String {
var newString:String;
var findCarriageReturnRegExp:RegExp = new RegExp("\r", "gi");
newString = $myString.replace(findCarriageReturnRegExp, "");
var findNewLineRegExp:RegExp = new RegExp("\n", "gi");
newString = newString.replace(findNewLineRegExp, "");
return newString;
}
我想说最简单的方法是听文本输入,像这样:
var t:TextArea = this.ta; //ta is on the timeline
t.restrict = "0-9"; //restricts the input only to numbers
t.addEventListener(TextEvent.TEXT_INPUT, onTextInput, true); //use capture phase to be able to prevent the default behavior (text input)
function onTextInput(e:TextEvent):void {
if(e.text.indexOf("\n") > -1) {
e.preventDefault(); //prevent the default behavior of the field
}
}
我现在无法对此进行测试,但我想它应该可以正常工作。