RxJs groupBy 带有一组对象,每个对象都有键和值数组

RxJs groupBy with an array of objects each having key and values array

所以要求是这样的: 我得到了一个对象数组(例如 Array)

[
   { empDept: 'Engineering', empLoc: 'Pune', empName: 'John' },
   { empDept: 'Engineering', empLoc: 'Mumbai', empName: 'Harry' },
   { empDept: 'HR', empLoc: 'Pune', empName: 'Denis' },
   { empDept: 'Finance', empLoc: 'Mumbai', empName: 'Elvis' },
]

我将有一个函数接受 属性 的名称作为参数,员工列表将根据该名称进行分组。所以如果输入参数值为'empDept',那么我想要的结果如下:

[
   {
      key: 'Engineering',
      values: [
         { empDept: 'Engineering', empLoc: 'Pune', empName: 'John' },
         { empDept: 'Engineering', empLoc: 'Mumbai', empName: 'Harry' },
     ]
   },
   {
      key: 'HR',
      values: [
         { empDept: 'HR', empLoc: 'Pune', empName: 'Denis' },
     ]
   },
   {
      key: 'Finance',
      values: [
        { empDept: 'Finance', empLoc: 'Mumbai', empName: 'Elvis' },
     ]
   }
]

我正在使用 RxJs groupBy 运算符来实现此目的。我试过下面的代码,但它似乎没有给出想要的结果:

this.groupedEmployees$ = employees$.pipe(
      groupBy(person => person.empDept),
      mergeMap(group => of({ key: group.key, values: group.pipe(mergeMap(x => toArray())) })),
    );

感谢您的帮助。

在这种情况下为什么要使用 rxjs?这纯粹是数组转换。你可以使用 lodash groupBy:https://lodash.com/docs/#groupBy


const t = [
   { empDept: 'Engineering', empLoc: 'Pune', empName: 'John' },
   { empDept: 'Engineering', empLoc: 'Mumbai', empName: 'Harry' },
   { empDept: 'HR', empLoc: 'Pune', empName: 'Denis' },
   { empDept: 'Finance', empLoc: 'Mumbai', empName: 'Elvis' },
];

const result = Object.entries(_.groupBy(t, 'empDept')).map(([key, values]) => ({key, values}));

您在找这样的东西吗?

function groupBy(key, array) {
  return array.reduce((all, current) => {
    const existingKey = all.find(existing => existing.key === current[key]);
    if (!existingKey) {
      all.push({key: current[key], values: [current]});
    } else {
      existingKey.values.push(current);
    }
    return all;
  }, []);
}

示例:

const arr = [
   { empDept: 'Engineering', empLoc: 'Pune', empName: 'John' },
   { empDept: 'Engineering', empLoc: 'Mumbai', empName: 'Harry' },
   { empDept: 'HR', empLoc: 'Pune', empName: 'Denis' },
   { empDept: 'Finance', empLoc: 'Mumbai', empName: 'Elvis' },
];

const byDept = groupBy('empDept', arr);
const byLoc = groupBy('empLoc', arr);

如果你真的想坚持使用 RxJS,你可以使用这段代码:

import { from } from 'rxjs'; 
import { groupBy, mergeMap, reduce, toArray } from 'rxjs/operators';

const groupedEmployees$ = from([
  { empDept: 'Engineering', empLoc: 'Pune', empName: 'John' },
  { empDept: 'Engineering', empLoc: 'Mumbai', empName: 'Harry' },
  { empDept: 'HR', empLoc: 'Pune', empName: 'Denis' },
  { empDept: 'Finance', empLoc: 'Mumbai', empName: 'Elvis' }
]).pipe(
  groupBy(person => person.empDept),
  mergeMap(group => group
    .pipe(
      reduce((acc, cur) => {
          acc.values.push(cur);
          return acc;
        },
        { key: group.key, values: [] }
      )
    )
  ),
  toArray()
);

groupedEmployees$.subscribe(console.log);