如何访问 json 中的嵌套值

Question

我正在尝试使用 api 和 python 从 scopus 获取数据。我使用 python 模块请求进行查询。查询的响应为我提供了一个 json，其值如下所示。

{ "search-results"：{ "opensearch:totalResults": "1186741", "opensearch:startIndex": "0", "opensearch:itemsPerPage": "25", "opensearch:Query"：{ "@role": "request", "@searchTerms": "all(machine learning)", "@startPage": "0" }, "link"：[ { "@_fa": "true", "@ref": "self", "@href": "api query", “@类型”："application/json" }, { "@_fa": "true", "@ref": "first", "@href": "api query", “@类型”："application/json" }, { "@_fa": "true", "@ref": "next", "@href": "api query", “@类型”："application/json" }, { "@_fa": "true", "@ref": "last", "@href": "api query", “@类型”："application/json" } ], "entry": [ { "@_fa": "true", "link"：[ { "@_fa": "true", "@ref": "self", "@href": "https://api.elsevier.com/content/abstract/scopus_id/85081889595" }, { "@_fa": "true", “@ref”："author-affiliation"， "@href": "https://api.elsevier.com/content/abstract/scopus_id/85081889595?field=author,affiliation" }, { "@_fa": "true", “@ref”："scopus"， "@href": "https://www.scopus.com/inward/record.uri?partnerID=HzOxMe3b&scp=85081889595&origin=inward" }, { "@_fa": "true", “@ref”："scopus-citedby"， "@href": "https://www.scopus.com/inward/citedby.uri?partnerID=HzOxMe3b&scp=85081889595&origin=inward" } ], "prism:url": "https://api.elsevier.com/content/abstract/scopus_id/85081889595", "dc:identifier": "SCOPUS_ID:85081889595", "eid": "2-s2.0-85081889595", "dc:title": "Recognizing hotspots in Brief Eclectic Psychotherapy for PTSD by text and audio mining", "dc:creator": "Wiegersma S.", "prism:publicationName": "European Journal of Psychotraumatology", "prism:issn": "20008198", "prism:eIssn": "20008066", "prism:volume": "11", "prism:issueIdentifier": "1", "prism:pageRange"：空， "prism:coverDate": "2020-12-31", "prism:coverDisplayDate": "2020 年 12 月 31 日", "prism:doi": "10.1080/20008198.2020.1726672", "citedby-count": "0", "affiliation": [ { "@_fa": "true", "affilname": "University of Twente", "affiliation-city": "Enschede", "affiliation-country": "Netherlands" } ], "prism:aggregationType": "Journal", "subtype": "ar", "subtypeDescription": "Article", "article-number": "1726672", "source-id": "21100394256", "openaccess": "1", "openaccessFlag": 是的 },

但是，响应是嵌套的 json，我无法访问它的内部元素，例如键 dc:creator、citedby-count 等

任何人都可以帮助我如何访问它的所有部分，例如作者姓名、引用者、隶属关系等。我想将此结果存储为 csv，我可以将其用于进一步的操作。

直接应用

df = pandas.read_json(文件名)

没有产生正确的结果格式：我得到这样的 table。

entry [{'@_fa': 'true', 'link': [{'@_fa': 'true', '@... link [{'@_fa': 'true', '@ref': 'self', '@href': 'ht... opensearch:Query {'@role': 'request', '@searchTerms': 'all(mach... opensearch:itemsPerPage 25 opensearch:startIndex 0 opensearch:totalResults 1186741

我也试过通过嵌套字典访问列表到字典的方法，但在某些时候，我卡住了。

with open('data.json', encoding='utf-8') as access:
      read_file = json.load(access)

…

type(read_file)

这是一个字典，所以我按照字典的语法进一步访问，它会在某个时候转换为列表，然后再次转换为字典。

我的主要要求是 - **如何创建一个包含 headers 列的 csv 文件，它是条目标签内的标签，例如 dc:identifier、dc:title、dc:creator , citedby-count 等，以及其中的值 ** 在此处输入代码

Answer 1

import json
dict_data = json.loads(response)
print(dict_data['key'])

你是这个意思吗？

如何访问 json 中的嵌套值

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