使用 php 在 pgadmin 上更改密码时出现问题

Question

我正在写一个 PHP 文件来允许用户更改他们的密码，但我遇到了一个奇怪的问题。我需要旧密码来确认帐户和新密码。鉴于凭据正确，此页面总是 returns 我认为用户密码不正确，因此 returns 第 12 行的回显 "Old password wrong"。如果我在 pgAdmin 查询工具中启动 "select * from utente" 来查看密码，我在密码框中看不到任何更改。然后，如果我返回表单更改密码，如果我在旧密码框中输入我之前想更改的新密码，但似乎没有被接受，因为以前没有识别出旧密码，程序成功。我发誓我不明白为什么。我认为这是 md5 中的错误，但它也不适用于 sha1。我知道两者都不安全，但现在我必须使用其中之一。我该如何解决？提前致谢

<?php
    $dbconn = pg_connect("host=localhost port=5432 dbname=progetto user=postgres password=password")
    or die('Could not connect:' . pg_last_error());
    if(!(isset($_POST['changeButton']))){
        header("Location: utente.php");
    }else{
        $email = $_COOKIE["cookieEmail"];
        $oldPassword = sha1($_POST['oldpassword']);
        $q1="select * from utente where email =  and password = ";
        $result=pg_query_params($dbconn,$q1,array($email, $oldPassword));
        if($line=pg_fetch_array($result ,null ,PGSQL_ASSOC)){
            echo "<h1>Old password wrong</h1>
            <a href=formCambiaPassword.php>Click here</a>";
        }else{
            $newPassword = sha1($_POST['newpassword']);
            $q2 = "update utente set password= where email=";
            $result=pg_query_params($dbconn, $q2, array($newPassword, $email));
            if($result==true){
                $q3="select * from utente where email =  and password = ";
                $result=pg_query_params($dbconn,$q3,array($email, $newPassword));
                if($line=pg_fetch_array($result ,null ,PGSQL_ASSOC)){
                    echo "<h1>Error</h1>
                    <a href=formCambiaPassword.php>Click here</a>";
                }else{
                    header("Location: utente.php");
                }
            }else{
                echo "<h1>Error 2</h1>
                        <a href=formCambiaPassword.php>Click here</a>";
            }
        }
    }
?>

Answer 1

您的 if 语句在本应检查 false 时查找 true。

if(!pg_fetch_array($result ,null ,PGSQL_ASSOC)){

您的代码应如下所示：

<?php
$dbconn = pg_connect("host=localhost port=5432 dbname=progetto user=postgres password=password")
or die('Could not connect:' . pg_last_error());
if(!(isset($_POST['changeButton']))){
    header("Location: utente.php");
}else{
    $email = $_COOKIE["cookieEmail"];
    $oldPassword = sha1($_POST['oldpassword']);
    $q1="select * from utente where email =  and password = ";
    $result=pg_query_params($dbconn,$q1,array($email, $oldPassword));
    if(!pg_fetch_array($result ,null ,PGSQL_ASSOC)){
        echo "<h1>Old password wrong</h1>
        <a href=formCambiaPassword.php>Click here</a>";
    }else{
        $newPassword = sha1($_POST['newpassword']);
        $q2 = "update utente set password= where email=";
        $result=pg_query_params($dbconn, $q2, array($newPassword, $email));
        if($result==true){
            $q3="select * from utente where email =  and password = ";
            $result=pg_query_params($dbconn,$q3,array($email, $newPassword));
            if($line=pg_fetch_array($result ,null ,PGSQL_ASSOC)){
                echo "<h1>Error</h1>
                <a href=formCambiaPassword.php>Click here</a>";
            }else{
                header("Location: utente.php");
            }
        }else{
            echo "<h1>Error 2</h1>
                    <a href=formCambiaPassword.php>Click here</a>";
        }
    }
}
?>

使用 php 在 pgadmin 上更改密码时出现问题

problem changing password on pgadmin with php

php

mysql

pgadmin

change-password

phppgadmin