在句子列表中查找单词列表和 return 匹配的句子
Finding the List of words in List of Sentences and return the matching sentences
从句子列表和单词列表,如何return句子列表,前提是所有三个单词都与单词列表(八卦)相匹配。
求推荐。以下是示例列表。
listwords = [['people','suffering','acute'], ['Covid-19','Corona','like'], ['people','must','collectively']]
listsent = ['The number of people suffering acute hunger could almost double.',
'Lockdowns and global economic recession have',
'one more shock – like Covid-19 – to push them over the edge',
'people must collectively act now to mitigate the impact']
输出列表应该是第一个和最后一个句子,因为它们在 listwords 中有三个匹配的词。
预期输出为:
['The number of people suffering acute hunger could almost double.',
'people must collectively act now to mitigate the impact']
欢迎来到 Stack Overflow
试试这个解决方案:
listwords = [['people','suffering','acute'], ['Covid-19','Corona','like'], ['people','must','collectively']]
listsent = ['The number of people suffering acute hunger could almost double.',
'Lockdowns and global economic recession have',
'one more shock – like Covid-19 – to push them over the edge',
'people must collectively act now to mitigate the impact']
# interate through each sentence
for sentence in listsent:
# iterate through each group of words
for words in listwords:
# check to see if each word group is in the current sentence
if all(word in sentence for word in words):
print(sentence)
我评论了这些行,让您了解发生了什么事
代码的第一部分遍历列表中的每个句子
for sentence in listsent:
然后我们需要遍历单词列表中的单词组
for words in listwords
这就是事情变得有趣的地方。由于您有嵌套列表,我们需要检查以确保在句子中找到所有三个词
if all(word in sentence for word in words):
最后你可以打印出包含所有单词的每个句子
print(sentence)
你也可以把它放在一个函数中,return 找到句子作为一个新列表
listwords = [['people','suffering','acute'], ['Covid-19','Corona','like'], ['people','must','collectively']]
listsent = ['The number of people suffering acute hunger could almost double.',
'Lockdowns and global economic recession have',
'one more shock – like Covid-19 – to push them over the edge',
'people must collectively act now to mitigate the impact']
def check_words(listwords, listsent):
listsent_new = []
# interate through each sentence
for sentence in listsent:
# iterate through each group of words
for words in listwords:
# check to see if each word group is in the current sentence
if all(word in sentence for word in words):
listsent_new.append(sentence)
return listsent_new
if __name__ == '__main__':
print(check_words(listwords, listsent))
从句子列表和单词列表,如何return句子列表,前提是所有三个单词都与单词列表(八卦)相匹配。
求推荐。以下是示例列表。
listwords = [['people','suffering','acute'], ['Covid-19','Corona','like'], ['people','must','collectively']]
listsent = ['The number of people suffering acute hunger could almost double.',
'Lockdowns and global economic recession have',
'one more shock – like Covid-19 – to push them over the edge',
'people must collectively act now to mitigate the impact']
输出列表应该是第一个和最后一个句子,因为它们在 listwords 中有三个匹配的词。
预期输出为:
['The number of people suffering acute hunger could almost double.',
'people must collectively act now to mitigate the impact']
欢迎来到 Stack Overflow
试试这个解决方案:
listwords = [['people','suffering','acute'], ['Covid-19','Corona','like'], ['people','must','collectively']]
listsent = ['The number of people suffering acute hunger could almost double.',
'Lockdowns and global economic recession have',
'one more shock – like Covid-19 – to push them over the edge',
'people must collectively act now to mitigate the impact']
# interate through each sentence
for sentence in listsent:
# iterate through each group of words
for words in listwords:
# check to see if each word group is in the current sentence
if all(word in sentence for word in words):
print(sentence)
我评论了这些行,让您了解发生了什么事
代码的第一部分遍历列表中的每个句子
for sentence in listsent:
然后我们需要遍历单词列表中的单词组
for words in listwords
这就是事情变得有趣的地方。由于您有嵌套列表,我们需要检查以确保在句子中找到所有三个词
if all(word in sentence for word in words):
最后你可以打印出包含所有单词的每个句子
print(sentence)
你也可以把它放在一个函数中,return 找到句子作为一个新列表
listwords = [['people','suffering','acute'], ['Covid-19','Corona','like'], ['people','must','collectively']]
listsent = ['The number of people suffering acute hunger could almost double.',
'Lockdowns and global economic recession have',
'one more shock – like Covid-19 – to push them over the edge',
'people must collectively act now to mitigate the impact']
def check_words(listwords, listsent):
listsent_new = []
# interate through each sentence
for sentence in listsent:
# iterate through each group of words
for words in listwords:
# check to see if each word group is in the current sentence
if all(word in sentence for word in words):
listsent_new.append(sentence)
return listsent_new
if __name__ == '__main__':
print(check_words(listwords, listsent))