创建 JSON 迅捷JSON
CREATE JSON SWIFTYJSON
我正在尝试创建一个像这样的json
[
{"key": "value"},
{"key": "value"},
{"key": "value"}
]
这是我的代码
var array: JSON = []
for i in (0..<obj.count){
array = [
"user": obj[i].name!,
"apikey": obj[i].key!
]
}
但是当我尝试打印时,只有第一项,
我该如何解决
使用Codable
。由于 Swift 4 SwiftyJSON
已过时
struct Object : Encodable {
private enum CodingKeys : String, CodingKey { case name = "user", key = "apikey" }
let name, key : String
}
let obj = [Object(name: "Foo", key: "API123"), Object(name: "Bar", key: "API456")]
do {
let jsonData = try JSONEncoder().encode(obj)
let jsonString = String(data: jsonData, encoding: .utf8)!
print(jsonString)
} catch { print(error) }
我正在尝试创建一个像这样的json
[
{"key": "value"},
{"key": "value"},
{"key": "value"}
]
这是我的代码
var array: JSON = []
for i in (0..<obj.count){
array = [
"user": obj[i].name!,
"apikey": obj[i].key!
]
}
但是当我尝试打印时,只有第一项, 我该如何解决
使用Codable
。由于 Swift 4 SwiftyJSON
已过时
struct Object : Encodable {
private enum CodingKeys : String, CodingKey { case name = "user", key = "apikey" }
let name, key : String
}
let obj = [Object(name: "Foo", key: "API123"), Object(name: "Bar", key: "API456")]
do {
let jsonData = try JSONEncoder().encode(obj)
let jsonString = String(data: jsonData, encoding: .utf8)!
print(jsonString)
} catch { print(error) }