使用 Twitter Fabric 检索我自己的帐户推文

Using Twitter Fabric to retrieve my own account tweets

我目前正在使用 twitter fabric 框架并尝试检索我自己的帐户推文列表。我尝试在线搜索无济于事。文档中的示例显示了如何显示基于 tweetID 的推文。我不要那个。我确实理解 REST 客户端与提供的变量建立 http 连接并检索 JSON 结果以进行解析等

这是我当前的代码,成功登录后会显示另一个 activity,我希望在这里显示我的推文。

          public void success(Result<TwitterSession> result) {
            // Do something with result, which provides a TwitterSession for making API calls
            TwitterSession session = Twitter.getSessionManager().getActiveSession();
            TwitterAuthToken authToken = session.getAuthToken();
            token = authToken.token;
            secret = authToken.secret;
            Log.i("token",token);
            Log.i("secret",secret);
            successNewPage();
        }

我还使用 intent

将令牌和密钥传递给了下一个 activity
   public void successNewPage(){
    Intent intent = new Intent(this, LoginSuccess.class);
    intent.putExtra("token",token);
    intent.putExtra("secret", secret);
    startActivity(intent);
}

在新的 activity class 上,我按照他们的文档得出了这个,

  TwitterAuthConfig authConfig =  new TwitterAuthConfig("consumerKey", "consumerSecret");
    Fabric.with(this, new TwitterCore(authConfig), new TweetUi());

    TwitterCore.getInstance().logInGuest(new Callback() {

        public void success(Result appSessionResult) {

            //Do the rest API HERE
            Bundle extras = getIntent().getExtras();
            String bearerToken = extras.getString("token");
            try {
                fetchTimelineTweet(bearerToken);
            } catch (IOException e) {
                e.printStackTrace();
            }

        }


        public void failure(TwitterException e) {
            Toast.makeText(getApplicationContext(), "Failure =)",
                    Toast.LENGTH_LONG).show();
        }

    });
}

推文的检索将是:

 // Fetches the first tweet from a given user's timeline
private static String fetchTimelineTweet(String endPointUrl)
        throws IOException {
    HttpsURLConnection connection = null;



    try {
        URL url = new URL(endPointUrl);
        connection = (HttpsURLConnection) url.openConnection();
        connection.setDoOutput(true);
        connection.setDoInput(true);
        connection.setRequestMethod("GET");
        connection.setRequestProperty("Host", "api.twitter.com");
        connection.setRequestProperty("User-Agent", "anyApplication");
        connection.setRequestProperty("Authorization", "Bearer " +  endPointUrl);
        connection.setUseCaches(false);


        String res = readResponse(connection);
        Log.i("Response", res);
        return new String();
    } catch (MalformedURLException e) {
        throw new IOException("Invalid endpoint URL specified.", e);
    } finally {
        if (connection != null) {
            connection.disconnect();
        }
    }
}

我在日志中得到的是:

380-380/com.example.john.fabric W/System.err﹕ java.io.IOException: 指定的端点无效URL。

我的url错了吗?还是我在 endpointURL 中设置的 token 也错了? 任何建议将不胜感激。谢谢!

应该是这样,消息是由fetchTimelineTweet函数抛出的。这应该是由这一行引起的:URL url = new URL(endPointUrl); 告诉 endPointUrl 导致 MalformedURLException

编辑

根据Twitter Dev Page, you should put this as endpointURL : https://dev.twitter.com/rest/reference/get/statuses/user_timeline并传递用户屏幕名作为参数。

编辑 2

我认为你的代码应该是这样的:

private static String fetchTimelineTweet(String endPointUrl, String token) // this line
        throws IOException {
    HttpsURLConnection connection = null;

    try {
        URL url = new URL(endPointUrl);
        connection = (HttpsURLConnection) url.openConnection();
        connection.setDoOutput(true);
        connection.setDoInput(true);
        connection.setRequestMethod("GET");
        connection.setRequestProperty("Host", "api.twitter.com");
        connection.setRequestProperty("User-Agent", "anyApplication");
        connection.setRequestProperty("Authorization", "Bearer " +  token); // this line
        connection.setUseCaches(false);


        String res = readResponse(connection);
        Log.i("Response", res);
        return new String();
    } catch (MalformedURLException e) {
        throw new IOException("Invalid endpoint URL specified.", e);
    } finally {
        if (connection != null) {
            connection.disconnect();
        }
    }
}