对象 es6 的条件解构数组

Question

堆栈闪电战：demo

思路是服务器发送如下格式的响应，需要根据以下条件决定在页面上显示或隐藏按钮，每个按钮都有单独的点击功能。这就是我在页面中静态声明按钮的方式。

我下面有一组对象。我需要在某些条件下将对象的属性映射到其他属性。

collections = [
  {
    "productId": "samsung",
    "productParams": "",
    "isAvailable": true
  },
  {
    "productId": "nokia",
    "productParams": "",
    "isAvailable": true
  },
  {
    "productId": "Lg",
    "productParams": "",
    "isAvailable": false
  },
]

这是对象的集合数组。这里我尝试根据两个条件来映射对象的属性，

如果 productId 值匹配 'string' 和 isAvailable 属性是 true 我已经分配给全局变量并显示按钮。但它是错误的。任何人帮助代码我做错了。

getClick() {
  let showButtonSamsung, showButtonNokia, showButtonLg;
  let x = this.collections.map(x => {
    showButtonSamsung = x.productId == 'samsung' && x.isAvailable == true ? true : false;
    showButtonNokia = x.productId =='nokia' && x.isAvailable == true ? true : false;
    showButtonLg = x.productId == 'Lg' && x.isAvailable == true ? true : false;
  });
}

预计O/P：

showButtonSamsung: true  // will show the button
showButtonNokia: true  // will show the button
showButtonLg: false  // hide the button

Answer 1

我认为在这种情况下 reduce 会好得多。

let collections = [{
    "productId": "samsung",
    "productParams": "",
    "isAvailable": true
  },
  {
    "productId": "nokia",
    "productParams": "",
    "isAvailable": true
  },

  {
    "productId": "Lg",
    "productParams": "",
    "isAvailable": false
  }
]


const map = {
  samsung: "showButtonSamsung",
  nokia: "showButtonNokia",
  Lg: "showButtonLg"
}

const {showButtonSamsung, showButtonNokia, showButtonLg} = collections.reduce((acc, obj) => {
  const property = map[obj.productId];
  acc[property] = obj.isAvailable;
  return acc;
}, {})

console.log(showButtonSamsung, showButtonNokia, showButtonLg);

Answer 2

我认为这或多或少是您要找的：

 const collections = [
    {
        "productId": "samsung",
        "productParams": "",
        "isAvailable": true
    },
    {
        "productId": "nokia",
        "productParams": "",
        "isAvailable": true
    },

    {
        "productId": "Lg",
        "productParams": "",
        "isAvailable": false
    }];

let isAvailable = (brand, collections) => collections.some((x) => x.productId === brand && x.isAvailable) 

let x = {
    showButtonSamsung: isAvailable('samsung', collections),
    showButtonNokia: isAvailable('nokia', collections),
    showButtonLg: isAvailable('Lg', collections),
}
console.log(x);

另一种选择：

let x = {
    showButtonSamsung: 'samsung',
    showButtonNokia: 'nokia',
    showButtonLg: 'Lg',
}


let isAvailable = (brand, collections) => collections.some((x) => x.productId === brand && x.isAvailable)
x = Object.entries(x).map(([key, value]) => ([key, isAvailable(value, collections)]))
    .reduce((obj, arr) => ({
        ...obj, [arr[0]]: arr[1]
    }), {})

console.log(x);

对象 es6 的条件解构数组

Conditional destructuring array of objects es6

javascript

destructuring

typescript

ecmascript-6

ecmascript-2016