pytest 模拟 pathlib.Path.open
pytest-mock pathlib.Path.open
我需要使用 pytest-mock
模拟 pathlib.Path.open
。
真正的open_func
开一个yaml-file
。 return 值是一个常规值 dict
。我如何模拟 Path.open
来加载另一个名为 test-config.yaml
的 yaml-file
?
我的代码无法正常工作,因为 conf
只会变成 str
("test_config.yaml")。应该是 dict
.
from pathlib import Path
import yaml
def open_func():
with Path.open(Path("./config.yaml")) as f:
return yaml.load(f, Loader=yaml.FullLoader)
def test_open_func(mocker):
mocker.patch("pathlib.Path.open", mocker.mock_open(read_data="test_config.yaml"))
conf = open_func()
assert isinstance(conf, dict)
编辑:
为了更接近我的现实世界问题,我提供了以下代码。我有一个 class TryToMock
,它基本上将两个文件作为输入。 load_files
方法只是加载这些文件(实际上是 .yaml 文件)并 return 输出。这些.yaml文件实际上是一些配置文件。
在我的单元测试中,我将通过 pytest 的 parametrize
调用 TryToMock
无数次。因此,我想通过 fixture
加载原始配置文件。然后我可以在 运行 load_files
.
之前的各种测试中 monkeypatch
一些条目
为了不再次加载原文件,我需要mockTryToMock
中的Path.open
函数。我想传递 monkeypatched
yaml 文件(即 dict
的形式)。困难在于我必须区分这两个文件。那就是我不能简单地用相同的文件内容模拟 Path.open
函数。
# TryToMock.py
from pathlib import Path
import yaml
# In my current working folder, I have to .yaml files containing the following
# content for illustrative purpose:
#
# file1.yaml = {'name': 'test1', 'file_type': 'yaml'}
# file2.yaml = {'schema': 'test2', 'currencies': ['EUR', 'USD', 'JPY']}
class TryToMock:
def __init__(self, file_to_mock_1, file_to_mock_2):
self._file_to_mock_1 = file_to_mock_1
self._file_to_mock_2 = file_to_mock_2
def load_files(self):
with Path.open(self._file_to_mock_1) as f:
file1 = yaml.load(f, Loader=yaml.FullLoader)
with Path.open(self._file_to_mock_2) as f:
file2 = yaml.load(f, Loader=yaml.FullLoader)
return file1, file2
# test_TryToMock.py
import os
from pathlib import Path
import pytest
import yaml
from tests import TryToMock
def yaml_files_for_test(yaml_content):
names = {"file1.yaml": file1_content, "file2.yaml": file2_content}
return os.path.join("./", names[os.path.basename(yaml_content)])
@pytest.fixture(scope="module")
def file1_content():
with Path.open(Path("./file1.yaml")) as f:
return yaml.load(f, Loader=yaml.FullLoader)
@pytest.fixture(scope="module")
def file2_content():
with Path.open(Path("./file2.yaml")) as f:
return yaml.load(f, Loader=yaml.FullLoader)
def test_try_to_mock(file1_content, file2_content, monkeypatch, mocker):
file_1 = Path("./file1.yaml")
file_2 = Path("./file2.yaml")
m = TryToMock.TryToMock(file_to_mock_1=file_1, file_to_mock_2=file_2)
# Change some items
monkeypatch.setitem(file1_content, "file_type", "json")
# Mocking - How does it work when I would like to use mock_open???
# How should the lambda function look like?
mocker.patch(
"pathlib.Path.open",
lambda x: mocker.mock_open(read_data=yaml_files_for_test(x)),
)
files = m.load_files()
assert files[0]["file_type"] == "json"
您必须将实际文件内容提供给 mock_open
的 read_data
参数。您可以只在测试中创建数据:
test_yaml = """
foo:
bar:
- VAR: "MyVar"
"""
def test_open_func(mocker):
mocker.patch("pathlib.Path.open", mocker.mock_open(read_data=test_yaml))
conf = open_func()
assert conf == {'foo': {'bar': [{'VAR': 'MyVar'}]}}
或者您可以从测试文件中读取数据:
def test_open_func(mocker):
with open("my_fixture_path/test.yaml") as f:
contents = f.read()
mocker.patch("pathlib.Path.open", mocker.mock_open(read_data=contents))
conf = open_func()
assert isinstance(conf, dict)
最后一个案例也可以重写以替换测试路径 open
调用中的 path
参数:
def test_open_func(mocker):
mocker.patch("pathlib.Path.open", lambda path: open("test.yaml"))
conf = open_func()
assert isinstance(conf, dict)
或者,如果您有针对不同配置的不同测试文件,例如:
def yaml_path_for_test(yaml_path):
names = {
"config.yaml": "test.yaml",
...
}
return os.path.join(my_fixture_path, names[os.path.basename(yaml_path)])
def test_open_func3(mocker):
mocker.patch("pathlib.Path.open", lambda path: open(yaml_path_for_test(path)))
conf = open_func()
assert isinstance(conf, dict)
这可能是您希望在测试代码中实现的。
更新:
这与问题的第二部分(编辑后)有关。如果您有预加载夹具文件的模块范围的夹具,那么您可以这样做:
def test_open_func(mocker, file1_content, file2_content):
def yaml_files_for_test(path):
contents = {"file1.yaml": file1_content,
"file2.yaml": file2_content}
data = contents[os.path.basename(path)]
mock = mocker.mock_open(read_data=yaml.dump(data))
return mock.return_value
mocker.patch("pathlib.Path.open", yaml_files_for_test)
conf = open_func()
assert isinstance(conf, dict)
或者,如果您不想使用嵌套函数:
def yaml_files_for_test(path, mocker, content1, content2):
contents = {"file1.yaml": content1,
"file2.yaml": content2}
data = contents[os.path.basename(path)]
mock = mocker.mock_open(read_data=yaml.dump(data))
return mock.return_value
def test_open_func5(mocker, file1_content, file2_content):
mocker.patch("pathlib.Path.open",
lambda path: yaml_files_for_test(path, mocker,
file2_content, file2_content))
conf = open_func()
assert isinstance(conf, dict)
我需要使用 pytest-mock
模拟 pathlib.Path.open
。
真正的open_func
开一个yaml-file
。 return 值是一个常规值 dict
。我如何模拟 Path.open
来加载另一个名为 test-config.yaml
的 yaml-file
?
我的代码无法正常工作,因为 conf
只会变成 str
("test_config.yaml")。应该是 dict
.
from pathlib import Path
import yaml
def open_func():
with Path.open(Path("./config.yaml")) as f:
return yaml.load(f, Loader=yaml.FullLoader)
def test_open_func(mocker):
mocker.patch("pathlib.Path.open", mocker.mock_open(read_data="test_config.yaml"))
conf = open_func()
assert isinstance(conf, dict)
编辑:
为了更接近我的现实世界问题,我提供了以下代码。我有一个 class TryToMock
,它基本上将两个文件作为输入。 load_files
方法只是加载这些文件(实际上是 .yaml 文件)并 return 输出。这些.yaml文件实际上是一些配置文件。
在我的单元测试中,我将通过 pytest 的 parametrize
调用 TryToMock
无数次。因此,我想通过 fixture
加载原始配置文件。然后我可以在 运行 load_files
.
monkeypatch
一些条目
为了不再次加载原文件,我需要mockTryToMock
中的Path.open
函数。我想传递 monkeypatched
yaml 文件(即 dict
的形式)。困难在于我必须区分这两个文件。那就是我不能简单地用相同的文件内容模拟 Path.open
函数。
# TryToMock.py
from pathlib import Path
import yaml
# In my current working folder, I have to .yaml files containing the following
# content for illustrative purpose:
#
# file1.yaml = {'name': 'test1', 'file_type': 'yaml'}
# file2.yaml = {'schema': 'test2', 'currencies': ['EUR', 'USD', 'JPY']}
class TryToMock:
def __init__(self, file_to_mock_1, file_to_mock_2):
self._file_to_mock_1 = file_to_mock_1
self._file_to_mock_2 = file_to_mock_2
def load_files(self):
with Path.open(self._file_to_mock_1) as f:
file1 = yaml.load(f, Loader=yaml.FullLoader)
with Path.open(self._file_to_mock_2) as f:
file2 = yaml.load(f, Loader=yaml.FullLoader)
return file1, file2
# test_TryToMock.py
import os
from pathlib import Path
import pytest
import yaml
from tests import TryToMock
def yaml_files_for_test(yaml_content):
names = {"file1.yaml": file1_content, "file2.yaml": file2_content}
return os.path.join("./", names[os.path.basename(yaml_content)])
@pytest.fixture(scope="module")
def file1_content():
with Path.open(Path("./file1.yaml")) as f:
return yaml.load(f, Loader=yaml.FullLoader)
@pytest.fixture(scope="module")
def file2_content():
with Path.open(Path("./file2.yaml")) as f:
return yaml.load(f, Loader=yaml.FullLoader)
def test_try_to_mock(file1_content, file2_content, monkeypatch, mocker):
file_1 = Path("./file1.yaml")
file_2 = Path("./file2.yaml")
m = TryToMock.TryToMock(file_to_mock_1=file_1, file_to_mock_2=file_2)
# Change some items
monkeypatch.setitem(file1_content, "file_type", "json")
# Mocking - How does it work when I would like to use mock_open???
# How should the lambda function look like?
mocker.patch(
"pathlib.Path.open",
lambda x: mocker.mock_open(read_data=yaml_files_for_test(x)),
)
files = m.load_files()
assert files[0]["file_type"] == "json"
您必须将实际文件内容提供给 mock_open
的 read_data
参数。您可以只在测试中创建数据:
test_yaml = """
foo:
bar:
- VAR: "MyVar"
"""
def test_open_func(mocker):
mocker.patch("pathlib.Path.open", mocker.mock_open(read_data=test_yaml))
conf = open_func()
assert conf == {'foo': {'bar': [{'VAR': 'MyVar'}]}}
或者您可以从测试文件中读取数据:
def test_open_func(mocker):
with open("my_fixture_path/test.yaml") as f:
contents = f.read()
mocker.patch("pathlib.Path.open", mocker.mock_open(read_data=contents))
conf = open_func()
assert isinstance(conf, dict)
最后一个案例也可以重写以替换测试路径 open
调用中的 path
参数:
def test_open_func(mocker):
mocker.patch("pathlib.Path.open", lambda path: open("test.yaml"))
conf = open_func()
assert isinstance(conf, dict)
或者,如果您有针对不同配置的不同测试文件,例如:
def yaml_path_for_test(yaml_path):
names = {
"config.yaml": "test.yaml",
...
}
return os.path.join(my_fixture_path, names[os.path.basename(yaml_path)])
def test_open_func3(mocker):
mocker.patch("pathlib.Path.open", lambda path: open(yaml_path_for_test(path)))
conf = open_func()
assert isinstance(conf, dict)
这可能是您希望在测试代码中实现的。
更新: 这与问题的第二部分(编辑后)有关。如果您有预加载夹具文件的模块范围的夹具,那么您可以这样做:
def test_open_func(mocker, file1_content, file2_content):
def yaml_files_for_test(path):
contents = {"file1.yaml": file1_content,
"file2.yaml": file2_content}
data = contents[os.path.basename(path)]
mock = mocker.mock_open(read_data=yaml.dump(data))
return mock.return_value
mocker.patch("pathlib.Path.open", yaml_files_for_test)
conf = open_func()
assert isinstance(conf, dict)
或者,如果您不想使用嵌套函数:
def yaml_files_for_test(path, mocker, content1, content2):
contents = {"file1.yaml": content1,
"file2.yaml": content2}
data = contents[os.path.basename(path)]
mock = mocker.mock_open(read_data=yaml.dump(data))
return mock.return_value
def test_open_func5(mocker, file1_content, file2_content):
mocker.patch("pathlib.Path.open",
lambda path: yaml_files_for_test(path, mocker,
file2_content, file2_content))
conf = open_func()
assert isinstance(conf, dict)