如何创建可以接收对象的 [HttpPost]？

Question

我想通过 HttpResponseMessage 从我的客户端代码发送一个对象，并在服务器端读取该对象并将 userId 保存在旁边。

我的客户端是这样的：

public async Task<ViewResult> Add(Car car)
{
        Car c;

        using (Database db = new Database())
        {
            c = db.Cars.First(x => x.Id == car.Id);
        }

        HttpClient client = new HttpClient();
        string json = JsonConvert.SerializeObject(c);
        HttpContent httpContent = new StringContent(json);           

        string url = "https://localhost:5001/api/cars/Saved/userId = " + AccountController.curentUser;    
        HttpResponseMessage response = await client.PostAsync(url, httpContent);

        return View("~/Views/Car/PreviewCar.cshtml");
}

在服务器端，它应该看起来像这样

[HttpPost("Saved/userId = {userId}")]
public async Task<ActionResult<CarS>> PostSavedCar(string userId) 
{
        // car = get from client side 

        car.UserId = userId;
        _context.SavedCars.Add(car);
        await _context.SaveChangesAsync();

        return CreatedAtAction("GetSavedCar", new { id = car.Id }, car);
}

我不知道应该在那个评论区放什么来获取对象然后反序列化它？

Answer 1

在您的客户端中设置内容类型 json:

HttpContent httpContent = new StringContent(json, Encoding.UTF8,"application/json");

还有你的 Api :

[HttpPost("Saved/userId = {userId}")]
public async Task<ActionResult<CarS>> PostSavedCar([FromBody]Car car, string userId) 
{
       car.UserId = userId;
        _context.SavedCars.Add(car);
        await _context.SaveChangesAsync();

        return CreatedAtAction("GetSavedCar", new { id = car.Id }, car);
}

实际上您不需要单独传递 userId - 为什么不在客户端设置 car.UserId 因为您已经知道它是什么值（或者更好的是，在服务器端设置它）？这样你就可以在请求正文中传递汽车。

如何创建可以接收对象的 [HttpPost]？

How to create [HttpPost] that can receive an object?

c#

rest

server-side

http-post

httpresponsemessage